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evablogger [386]
3 years ago
12

Evaluate the expression when b=2 . b⋅5 = Answer:

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

b*5 = 10

Step-by-step explanation:

Given

b = 2

Required

Evaluate b*5

To do this, we simply substitute 2 for b in b*5

b*5 = 2 * 5

b*5 = 10

<em>The result of the expression is 10</em>

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A diesel train left Abuja and traveled west.Two hours later a freight train left traveling 15 mph faster in an effort to catch u
Zepler [3.9K]

Step-by-step explanation:

let the speed of diesel train = x

the equation would be:

(2+6)x = 6(x+15)

8x = 6x+90

8x-6x = 90

2x = 90

x = 90/2

x = 45

Therefore, the speed of diesel train =

45 mph

8 0
3 years ago
A plane headed due south is traveling with an airspeed of 160 miles per
lord [1]

Answer:

60 °

Step-by-step explanation:

Applying the law of sine we have the following:

160 / Sin B = 80 / Sin 30 °

We solve for B and we have:

160 / Sin B = 80 / 0.5

160 / Sin B = 160

Without B = 160/160

B = Arc Sin (1)

B = 90 °

Now to calculate the other angle (true

 course) would be:

A = 180 ° - (B + C)

A = 180 ° - (90 ° + 30 °)

A = 60 °

That is to say that true course is 60 °

5 0
3 years ago
1/(x-1)x+1/x(x+1)+...+1/(x+9)(x+10)=11/12
nata0808 [166]

Notice that

\dfrac1{(x-1)x} = \dfrac1{x-1} - \dfrac1x \\\\ \dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1} \\\\ \vdots \\\\ \dfrac1{(x+9)(x+10)} = \dfrac1{x+9} - \dfrac1{x+10}

That is, the <em>n</em>-th term (where <em>n</em> = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of

\dfrac{1}{(x+n)(x+n+1)} = \dfrac1{x+n} - \dfrac1{x+n+1}

and in the sum, some adjacent terms will cancel and leave you with

\dfrac1{(x-1)x} + \dfrac1{x(x+1)} + \cdots + \dfrac1{(x+9)(x+10)} = \dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Now solve for <em>x</em>, bearing in mind that we cannot have <em>x</em> = 0, -1, -2, …, -10 :

\dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Combine the fractions on the left side:

\dfrac{(x+10)-(x-1)}{(x-1)(x+10)} = \dfrac{11}{(x-1)(x+10)} = \dfrac{11}{12}

Then we must have

(x-1)(x+10) = x^2 + 9x - 10 = 12 \implies x^2+9x-22 = (x+11)(x-2) = 0

so that either <em>x</em> = 2 or <em>x</em> = -11.

4 0
3 years ago
PLEASE HELP What is the rule for the sequence with the first four terms below?
ivolga24 [154]

Answer:

A) [First try is correct for all U1 to U4]

Step-by-step explanation:

1. Trying each option

(let x = 1,2,3,4) since it goes from U1 to U4 (Geometric sequence)

A.) 10(-4/5)^x

10(-4/5)^1 = -8

10(-4/5)^2 = 6.4

10(-4/5)^3 = -5.12

10(-4/5)^4 = 4.096

3 0
3 years ago
If all three dimensions of a rectangular prism are quadrupled, then how will the new surface area compare to the old surface are
castortr0y [4]
Let the initial width, depth and height of the prism be w, d, and h respectively.
surface area of a rectangular prism is 2(w * d + w * h + d * h).

After quadrupling the dimentions, new dimentions is 4w, 4d and 4h.
New surface area is 2(4w * 4d + 4w * 4h + 4d * 4h) = 2(16 * w * d + 16 * w * h + 16 * d * h) = 16 * 2(w * d + w * h + d * h)

Ratio of old surface area to new surface area is 2(w * d + w * h + d * h) : 16 * 2(w * d + w * h + d * h) = 1 : 16
7 0
3 years ago
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