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3 years ago

Evaluate the expression when b=2 . b⋅5 = Answer:

Mathematics

1 answer:

ddd [48]3 years ago

7 0

Answer:

$b*5 = 10$

Step-by-step explanation:

Given

$b = 2$

Required

Evaluate $b*5$

To do this, we simply substitute 2 for b in $b*5$

$b*5 = 2 * 5$

$b*5 = 10$

<em>The result of the expression is 10</em>

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Anyone know quadratics

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${b}^{2}$
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$2bx$
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3 years ago

Find three points of the linear equation -x-2y=-10

n200080 [17]

We can find 3 points by plugging them in

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4 years ago

Sammy is classifying quadrilateral EFGH. How can she use coordinate geometry to determine whether EFGH is a rhombus?

dmitriy555 [2]

Answer:

Step-by-step explanation:

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3 years ago

In triangle JKL, tan(b°) = 3/4 and cos(b°) =4/5. If triangle JKL is dilated by a scale factor of 1/2, what is sin(b°)?

zysi [14]

Answer:

$\sin (b^\circ)=\dfrac{3}{5}$ .

Step-by-step explanation:

It is given that,

$\tan (b^\circ)=\dfrac{3}{4}$

$\cos (b^\circ)=\dfrac{4}{5}$

If a figure is dilated, then the image is similar to the figure. It means the corresponding angles of figure and image are congruent.

So, the value of sin(b°) after dilation is equal to the value of sin(b°) before dilation.

We know that,

$\dfrac{\sin \theta}{\cos \theta}=\tan \theta$

$\dfrac{\sin (b^\circ)}{\cos (b^\circ)}=\tan (b^\circ)$

$\sin (b^\circ)=\tan (b^\circ)\times \cos (b^\circ)$

$\sin (b^\circ)=\dfrac{3}{4}\times \dfrac{4}{5}$

$\sin (b^\circ)=\dfrac{3}{5}$

Therefore, $\sin (b^\circ)=\dfrac{3}{5}$ .

5 0

4 years ago

Yea.....can sum1 help pls

vichka [17]

Answer:

208

Step-by-step explanation:

8*8=64

9*8/2=36

36*4=144

144+64=208

have a nice day :)

8 0

3 years ago

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