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3 years ago

How do i solve tis in need help slope=2/7 y-intercept=-4

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

5 0

Answer:

y=2/7x-4

Step-by-step explanation:

Write in Slope intercept form

y=mx+b

m = slope

b = y intercept

x = x intercept

y = (0,-4)

So,

y = 2/7x+(-4) substitute

y = 2/7x-4

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A boy weighs 31.5 kilograms. how much does he weigh in pounds? use the following conversion: 1 kilogram is 2.2 pounds

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The equation y+6=1/3(x-9) is written in point-slope form. What is the equation written in slope-intercept form?

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see explanation

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y = mx + c ( m is the slope and c the y- intercept )

Given

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4 years ago

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ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago

Please help. I don't understand how to do this. I need this asap. please

Schach [20]

9514 1404 393

Answer:

r = 1/9

Step-by-step explanation:

First of all, solve the equation for r:

y = rx

y/x = r . . . . . . . divide by x

Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.

r = y/x = 5/45

r = 1/9 . . . . . . . . . reduced fraction

_____

<em>Additional comment</em>

It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:

y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value

6 0

3 years ago