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Mnenie [13.5K]
3 years ago
10

Simplify 2y^4x5y^3 pleaseeeeeeeeeeeee

Mathematics
1 answer:
Setler [38]3 years ago
7 0
10y^2 times 4x times 3
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Subtract: 2x^2 - 4x - 3 from x^2 - 5x - 8.
lesya692 [45]
The answer is: -x^2-x-5           
8 0
3 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
Melissa has three different positive integers. She adds their reciprocals together and gets a sum of 1. What is the product of h
sergiy2304 [10]
The integers would be 2,3, and 6.

Check:

1/2+1/3+1/6=3/6+2/6+1/6=6/6= 1 

Hope this helped, and if it did, then please vote brainliest!
7 0
4 years ago
How would I know what similarity it is?
muminat

Answer:

I can't see the ques

Step-by-step explanation:

Can u please post it again

8 0
3 years ago
Mrs. Roberts has a square garden with an area of 36 square feet. She wants to put a fence around only 3 sides of her garden. How
Nesterboy [21]

Answer:

27 feet.

Step-by-step explanation:

This is quite simple. As a square has equal lenght and width we can tell that 6x6=36. So each side has a lenght of 6 feet.  With only 3 sides needed for fencing, 6x3=27. Mrs. Roberts needs 27 feet of fencing.

6 0
3 years ago
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