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Sedbober [7]
3 years ago
5

How many times do you need to regroup to subtract 316 from 624?

Mathematics
1 answer:
ss7ja [257]3 years ago
5 0

you need to equal them out, so it is actually 48 over 56 (times by 8) subtract 7 over 56 (times by 7). so the answer is 41 over 56.

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a rectangular prism has a top area of 20ft square and a height of 5ft. what is the volume of this rectangular prism
krok68 [10]
V = Bh
.. = (20 ft^2)*(5 ft)
.. = 100 ft^3

The volume of this rectangular prism is 100 ft^3.
7 0
3 years ago
Dewey buys 10 folders for $6.50. Orioles folders cost $0.50 each and Ravens folders cost $0.75 each. How many of each type of fo
Dennis_Churaev [7]

Answer: he bought 6 of the .75cent then 4 of the .50c

Step-by-step explanation:

4 0
3 years ago
Please explain this answer ☹️
GuDViN [60]

Answer:

see explanation

Step-by-step explanation:

Note that cos315° = cos45° and sin315° = - sin45° and

cos45° = sin45° = \frac{1}{\sqrt{2} } = \frac{\sqrt{2} }{2}

Hence

12(cos315° + isin315°)

= 12(cos45° - isin45°)

= 12(\frac{\sqrt{2} }{2} - i \frac{\sqrt{2} }{2})

= 6\sqrt{2} - 6i \sqrt{2}

7 0
3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
A practice field is 350 feet long. The game field is 40% longer than the practice field. How long is the game field?
kifflom [539]

Answer: 490 feet

Step-by-step explanation: Since the game field is 40% longer than the practice field, it is 140% or 1.4 times the practice field. 350•1.4 is 490 feet.

8 0
2 years ago
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