
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

AREA COVERED BY THE ANGLE IN A SEMI SPHERE


Total Area Of The Semi Sphere:-

Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-


Total Area - Area Under Unshaded Part


Answer:
97
Step-by-step explanation:
5 * 85 - 4* 82 = 97
Answer: m²-9mn+2n²
Step-by-step explanation: make use of BODMAS strategy. Let the unknown be x.
-7mn+2m²+3n²-x= m²+2mn+n². Since we are concerned about getting the unknown,let's try to collect the like terms.
-7mn+2m²+3n²-(m²+2mn+n²)= x
-7mn+2m²+3n²-m²-2mn-n²= x
-7mn-2mn+2m²-m²+3n²-n²=x
-9mn+m²+2mn= x
X= m²-9mn+2n²
Answer:
13.9283882772
Step-by-step explanation:
Pythagorean Theroem, so 5^2+13^2=194
Under square root 194=13.9283882772
Hope I helped!