It makes everything clear from a mathematical point , much easier to solve the question in equation form than trying to figure it out from a long word problem
Answer:
The volume increases at a rate of 
Step-by-step explanation:
The rate of change of the radius with respect to time is 4 mm / s.
So:

Now we must find a relationship between the volume of a sphere and its radius.
The equation of the volume of a sphere is:

So:

The diameter of the sphere is 100 mm. Therefore its radius is 100/2 = 50 mm.
So:

The volume increases at a rate of :
40000 π mm ^ 3 / s = 125663.71 mm^3/s
Answer:4(3x+4y)
Step-by-step explanation: the gcf of 12x+16y is 4. we factor out 4 by dividing both terms by 4.
Answer:
(X+10)(X-3)
Step-by-step explanation: