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Bogdan [553]
3 years ago
14

If f ( x ) = 2 x - 5, then f (4) is _____. 3 5 4 17

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0
The answer is 3

if you substitute x as 4 then it would be 2 x 4 = 8

8-5=3
mash [69]3 years ago
6 0
The answer is 3 because it just 3
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Suppose Austin, Texas, is hit by a tornado that destroys 25 percent of the housing in the area. Would you expect the total expen
notsponge [240]

Answer:

<u>greater than what it was before</u>

Step-by-step explanation:

<em>Remember</em>, a tornado usually causes significant structural damages to houses within its area of impact., and this requires running expenses to repair the damage.

Hence,<u> since the term </u><u>expenditure, </u><u>also implies expenses; we can expect the total expenditure on housing after the tornado to be </u><u>greater than</u><u> what it was before the tornado since families would be paying for repairs.</u>

4 0
3 years ago
Sarah buys 2 candy bars for $1.45. how much would one candy bar cost
sattari [20]
2 = $1.45
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4 0
3 years ago
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
kendra biked 10kilometers on monday .she biked twice as many kilometers on tuseday how many total meters did she bike
hram777 [196]

Answer:

10km+10km*2 = 30km

30km*(1000m/1km) = 30000m

In the second equation of the problem, the kilometers from the initial total distance biked is cancelled out by the conversion of kilometers to meters, as seen in the 1000m/1km (or 1000 meters for every 1 kilometer).

Read more on Brainly.com - brainly.com/question/454009#readmore

Step-by-step explanation:

5 0
3 years ago
Help please asap!!!!!!!!!
Anton [14]
I hope this helps you:)

8 0
3 years ago
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