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alexgriva [62]
2 years ago
7

Need help, I don’t understand this!

Mathematics
1 answer:
pychu [463]2 years ago
7 0
SSS is the answer!!!
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Find the domain x^2-25/2
Mumz [18]
For this, I am assuming that -25/2 is not a part of the exponent(although in future questions you should make this clear by using parenthesis.

When I do problems like this, I come to CBAD.  where the variables are y=A(Bx+C)+D

CBAD helps significantly in domain and range problems where there is a well known parent function.  (y=x^2, y=sqrt(x), y=1/x, y=x, etc).  Basically, if there is a parent function with slight additions(y=2*x^2, y=sqrt(x+1), y=1/(5x), y=3x, etc)

This works that in the order, a C term shifts the graph horizontally in the opposite direction expected (a negative number will shift right, a positive number will shift left).  For example, if C is -2, the graph of the parent function will shift right 2.
Then, a B term dilates(changes the horizontal size of the graph) by the factor 1/B(every x value is multiplied by 1/B).  Thus a B >1 will shrink the graph horizontally, and a 0<B<1 with stretch the graph horizontally.  If B is negative, it reflects the graph over the y axis and then either shrinks or stretches horizontally.  If B is 1, nothing changes.
Then, a A term dilates(changes the horizontal size of the graph) by the factor A(every y value is multiplied by A).  Thus a A >1 will stretch the graph vertically, and a 0<A<1 with shrink the graph vertically.  If A is negative, it reflects the graph over the x axis and then either shrinks or stretches vertically.  If A is 1, nothing changes.
Finally, a D term shifts the graph vertically in the direction expected (a negative number will shift down, a positive number will shift up).  For example, if D is -2, the graph of the parent function will shift down 2.

<u>Warning </u><u></u><u>CBAD must be performed in the order C-B-A-D</u>

Now that you know these simple rules and can memorize the few parent functions, you can figure out the domain and range of almost any function.  

In your case, the function x^(2)-25/2 is not much different than x^2, an upwards facing parabola centered at (0,0).  In fact, there is only one transformation, D, because C=0 (it is not shown), B=1(it is not shown), and A=1(it is not shown).  Thus the only difference between your graph and the parent function is that yours is shifted down by 25/2.  

For this reason, because the domain of x^2 is not restricted (it includes all real numbers), the domain of your new function is not restricted (it includes all real numbers).
8 0
3 years ago
Suppose there are two types of tickets to a show: advance and same day. The combined cost of one advance ticket and one same day
Debora [2.8K]

Answer:

Answer = $30.00 advanced and $36.00 same day.

Step-by-step explanation: We can replace 20:40 ratio.

30 x 20 and 70 x 20 = 600+ 800 =3/5  to find 2/4 = 12/20 finds 10/20 through HCF and hereafter we have one ticket is 1/6 more. So if 60 tickets were sold for 2000 then $33.33 would be the average and if one was 1/6 more than the other it is 0.5/6 higher than 33.33 =2.66 more = £36 for All day and £30 for Advanced tickets. 36 x 20 = $600  and 36 x 40 =$1400. We know its $30 as we can double check its ratio after. 20:40 is 1/2 but then take off $3 each side to balance back to find $60 combined. $2000=1400+$600 =1:2 and 2:4 ratio.

5 0
3 years ago
Complete the factorization of 3x2 – 5x + 2.
Schach [20]
3x² - 5x + 2 
= 3x² - 3x - 2x + 2
= 3x(x-1) - 2(x-1)
= (x-1)(3x-2)
4 0
3 years ago
Read 2 more answers
PLEASE SOMEONE DO THE DAY7 : TIME FOR ME. GIVING BRAINLIEST FOR WHOEVER GETS IT RIGHT!
Blababa [14]
1. 1 hour and 30 minutes 2. 11:35 : your welcome !
8 0
3 years ago
What is the solution of ?<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20x-7%3D%5Cfrac%7B3%7D%7B4%7D%20x%2B14" id="Tex
Nonamiya [84]

Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

Find the common denominator.

\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x(-7)}{2}=\dfrac{3}{4}x+14   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3}{4}x+14   }

Combine the multiplied terms into a single fraction

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+14   }

Find the common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+\dfrac{4\cdot14}{4}    }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+56}{4}   }

Eliminate the denominators of the fractions.

\bf{4\cdot\dfrac{5x-14}{2}=4\cdot\dfrac{3x+56}{4}   }

Cancel the multiplied terms that are in the denominator.

\bf{2(5x-14)=3x+56}

To distribute.

\bf{10x-28=3x+56 }

Add 28 to both sides.

\bf{10x-28+28=3x+56+28 }

Simplify

\bf{10x=3x+84 }

Subtract 3x from both sides.

\bf{10x-3x=3x+84-3x }

Simplify

\bf{7x=84 }

Divide both sides by the same factor.

\bf{x=\dfrac{84}{7} }

Simplify

\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
  9. \bf{23=23}

Checked ✅

3 0
2 years ago
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