Answer:
Explanation:
Given
Motorcyclist speed=12 m/s
maximum acceleration
distance=39 m
Let x be the distance traveled by motorist in his reaction time
therefore remaining 39-x will be traveled with 
acceleration
s=39-x
v=0
u=12 m/s
x=27 m
Therefore he traveled 27 m in his reaction time
t=2.25 s
(b)If his reaction time is 2.56 sec
then distance traveled in his reaction time
Remaining distance 39-30.72=8.28 m
therefore its velocity when it reaches the deer
v=6.681 m/s
Answer:
f = 5 cm
Explanation:
using the thin lens equation, given as follows:
where,
f = focal length = ?
do = the distance of object from lens = 20 cm
di = the distance of image from lens = 6.6667 cm
Therefore,
<u>f = 5 cm</u>
Answer:
8672
Explanation:
multiply the length value by 100
Answer:
4.7 GHz
Explanation:
Applying,
v = λf................. Equation 1
Where v = velocity of the radio wave, λ = wavelength, f = frequency
make f the subject of the equation
f = v/λ.............. Equation 2
Note: A radio wave is an electromagnetic wave, as such it moves with a velocity of 3.00 x 10⁸ m/s
From the question,
Given: λ = 0.0644 meters
Constant: v = <em>3.00 x 10⁸ m/s</em>
Substitute these values into equation 2
f = (3.00 x 10⁸)/0.0644
f = 4.66×10⁹ Hz
f = 4.7 GHz
