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2 years ago

A longitudinal wave is observed. Exactly 6 crests are observed

1 answer:

3 0

The speed of the wave is 1.58 meters per second (or 1.584 if you don’t round it).
You multiply wavelength by frequency to get the speed of a wave.
2.4 times 0.66 = 1.548 meters per second.

If you didn’t have the frequency before hand, you would just divide the 6 crests by the 9.1 seconds.

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An uncharged capacitor is connected to a 21-V battery until it is fully charged, after which it is disconnected from the battery

attashe74 [19]

Answer:

The voltage bewtween the plates will be 9.5V

Explanation:

Facts:

The capacitance of a parallel plate capacitor having plate area A and plate separation d is C=ϵ0A/d.

Where ϵ0 is the permittivity of free space.

A capacitor filled with dielectric slab of dielectric constant K, will have a new capacitance C1=ϵ0kA/d

C1=K(ϵ0A/d)

C1=KC ----------- 1

Where C is the capacitance with no dielectric and C1 is the capacitance with dielectric.

The new capacitance is k times the capacitance of the capacitor without dielectric slab.

This implies that the charge storing capacity of a capacitor increases k times that of the capacitor without dielectric slab.

Given points

• The terminal voltage of the battery to which the capacitor is connected to charge V=25V

• A dielectric slab of paraffin of dielectric constant K=2 is inserted in the space between the capacitor plates after the fully charged capacitor is disconnected

The charge stored in the original capacitor Q=CV

The charge stored in the original capacitor after inserting dielectric Q1=C1V1

The law of conservation of energy states that the energy stored is constant:

i.e Charge stored in the original capacitor is same as charge stored after the dielectric is inserted.

Q = Q1

CV = C1V1

 CV = C1V1 -------2

We derived C1=KC from equation 1. Inserting this into equation 2

CV = KCV1

V1 = (CV)/KC

V/K

= 21/2.2

= 9.5

4 0

3 years ago

A very small sphere with positive charge 5.00uC is released from rest at a point 1.20cm from a very long line of uniform linear

JulijaS [17]

Let us situate this on the x axis, and let our uniform line of charge be positioned on the interval (−L,0] for some large number L. The voltage V as a function of x on the interval (0,∞) is given by integrating the contributions from each bit of charge. Let the charge density be λ. Thus, for an infinitesimal length element dx′, we have λ=dqdx′.V(x)=1/4πϵ0∫linedq/r=λ/4πϵ0∫−L0dx/x−x′=λ/4πϵ0(ln|x+L|−ln|x|)

5 0

3 years ago

horrorfan [7]

Answer:

B. 6HgO → 6Hg + 3O $_{2}$

Explanation:

A decomposition reaction is a reaction in which a single reactant is broken down into 2 or more products.

6 0

3 years ago

Do help me pleaseeeee

Anton [14]

The mass needed at peg 1 is a 5g mass.

The 15g should hang at peg 5.

The reason is force x distance clockwise is equal to force x distance anti-clockwise

8 0

3 years ago

There are 8.8 liters of gas in a piston at a pressure of 1.75 atmospheres. The temperature remains constant, and the gas is comp

saveliy_v [14]

The new pressure P2 is 2.48 atmosphere.

Explanation:

Here, the one of the product of pressure and volume is equal to the products of pressure and volume of other.

By using Boyles's law,

pressure is inversely proportional to volume,

P1 V1 = P2 V2

where P1, V1 represents the first pressure and volume,

P2, V2 represents the second pressure and volume

P2 = (P1 V1) / V2

= (1.75 $\times$ 8.8) / 6.2

P2 = 2.48 atmosphere.

5 0

3 years ago