Answer:
Mila had $48 initially
Step-by-step explanation:
Let the amount of money they had be x
Mila spent $42; what is left would be x-42
Samuel spent $36: what is left would be x-36
So, what Mila had left is half of what Samuel has; that would be;
x-42 = 1/2(x-36)
2(x-42) = x -36
2x-84 = x -36
2x - x = 84 -36
x = $48
It’s A because 3 8’s are 24 but it’s not a mulitiple of 12
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

There’s 4 quarts in a gallon and the cost of 1 gallon ($3.89) divided by 4 is .97 cents. Which is less than the cost of 1 quart. Therefore buying the gallon is a better buy.