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3 years ago

8

Help plz:))) I’ll mark you BRAINLIEST

1 answer:

Wewaii [24]3 years ago

5 0

Answer:

i think it may be A.1 or E.5

Step-by-step explanation:

sorry if this is wrong

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A soccer field has a length of 100 yards and a width of 60 yards. Which equation can you use to find the area of the soccer fiel

snow_tiger [21]

Answer:

60 x 100

Step-by-step explanation:

Since the formula for area of a rectangle is length × width, multiplying the sides will get you the area.

CREDIT TO nilbert

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3 years ago

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Find the volume of this object

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$423 cm^{3}$

Step-by-step explanation:

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3 years ago

3 and 7/10 x 4 and 4/5<br> Please help<br> I want to now if my answer is correct

BabaBlast [244]

The answer is 17 and 19/25

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3 years ago

triangle ABC is isosceles, angle B is vertex angle , AB = 20x -2, AC =25x, and BC =12 x +20. Find x and the length of each side

lisov135 [29]

Length of AB = 18. 92

Length of AC = 26. 15

Length of BC = 32. 552

<h3>How to determine the sides of the triangle</h3>

Using the Pythagorean theorem, we have that

$(20 x-2)^2 = (12x + 20)^2 + (25x)^2$

Expand the bracket

$400x^2- 4 = 144x^2 + 400 + 625x^2$

Collect like terms

$400x^2 - 144x^2 - 625x^2 = 400 + 4$

$-369x^2 = 404$

Make x^2 subject

$x^2 = \frac{404}{369}$

$x = \sqrt{1.0948}$

$x = 1. 046$

Thus,

Length of AB = 20x -2 = 20(1. 046) - 2 = 18. 92

Length of AC = 25x = 25* 1.046 = 26. 15

Length of BC = 12x + 20 = 12(1. 046) + 20 = 32. 552

Learn more about isosceles triangles here:

brainly.com/question/1475130

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8 0

1 year ago

The daily average temperature in Santiago, Chile, varies over time in a periodic way that can be modeled approximately by a trig

natali 33 [55]

Answer:

a) the trigonometric function is;

$y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5$

b) $y = 28.36^0 \ C$ ( to two decimal places)

Step-by-step explanation:

This data can be represented by the sinusoidal function of the form :

$\mathbf{y = A sin (Bt -C)+D}$

where A = amplitude and which can be determined via the formula:

$A = \dfrac{largest \ temperature - lowest \ temperature}{2}$

$A = \dfrac{29-14}{2}$

$A = \dfrac{15}{2}$

A = 7.5° C

where B = the frequency;

Since the data covers a period of 3 days ; then $\dfrac{2 \pi}{B } =365$

$B = \dfrac{2 \pi}{365}$ ( where 365 is the time period )

The vertical shift is found by the equation D;

D = $\frac{largest \ temperature + lowest \ temperature}{2}$

D = $\frac{29+14}{2}$

D = 21.5

Replacing the values of A ; B and D into the above sinusoidal function; we have :

$y = 7.5 sin (\frac{2 \pi}{365}t -C) + 21.5$

From the question; when it is 7th of the year ( i.e January 7);

t = 7 and the temperature (y) = 29° C

replacing that too into the above equation; we have:

$29= 7.5 sin (\frac{2 \pi}{365}*7 -C) + 21.5$

$29= 7.5 sin (\frac{14 \pi}{365} -C) + 21.5$

$\frac{29-21.5}{7.5}= sin (\frac{14 \pi}{365} -C)$

$1= sin (\frac{14 \pi}{365} -C)$

$sin^{-1}(1)= (\frac{14 \pi}{365} -C)$

$\frac{\pi}{2}= (\frac{14 \pi}{365} -C)$

$C= (\frac{14 \pi}{365} -\frac{\pi}{2})$

$C= (\frac{28 \pi- 365 \pi}{730} )$

$C= \frac{-337 \pi}{730}$

Thus; the trigonometric function is;

$y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5$

Similarly; to determine the temperature o Jan 31; i.e when t= 31 ; we have :

$y = 7.5 sin ( \frac{2 \pi}{365}*31+ \frac{337 \pi}{730})+ 21.5$

$y = 7.5 sin ( \frac{62 \pi}{365}+ \frac{337 \pi}{730})+ 21.5$

$y = 7.5 sin ( \frac{124 \pi+ 337 \pi }{730})+ 21.5$

$y = 7.5 sin ( \frac{461 \pi }{730})+ 21.5$

$y = 7.5 *( 0.915)+ 21.5$

$y = 6.8689+ 21.5$

$y = 28.36^0 \ C$ ( to two decimal places)

7 0

3 years ago

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