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sertanlavr [38]
3 years ago
15

I need help with this question, I already know the answer but I need someone to explain step by step

Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

y=3x-5

Step-by-step explanation:

so step by step would go like this

1) add Y to the opposite side

3x=Y+5

2)Subtract 5 from the side with Y

y=3x-5

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An airplane makes a 400-mile trip against a head wind in 4 hours. The return trip takes 2.5 hours, the wind now being a tall win
tangare [24]

Answer:

v_p=130\ miles/h

v_w=30\ miles/h

Step-by-step explanation:

Lets call v_p the the still-air speed of the plane and v_w the speed of the wind. On the first part the speed of the plane relative to the ground will be v_1=v_p-v_w, and on the second part it will be v_2=v_p+v_w.

We know that the distance d=400 miles on the first and second parts are the same, so by the definition of velocity we will have:

v_1=\frac{d}{t1}

v_2=\frac{d}{t2}

Or:

v_p-v_w=\frac{d}{t1}

v_p+v_w=\frac{d}{t2}

Adding both equations:

(v_p-v_w)+(v_p+v_w)=2v_p=\frac{d}{t1}+\frac{d}{t2}

v_p=\frac{1}{2}(\frac{d}{t1}+\frac{d}{t2})

Which for our values is:

v_p=\frac{1}{2}(\frac{400\ miles}{4h}+\frac{400\ miles}{2.5h})=130\ miles/h

If instead of adding, we substact, we would have:

(v_p+v_w)-(v_p-v_w)=2v_w=\frac{d}{t2}-\frac{d}{t1}

v_w=\frac{1}{2}(\frac{d}{t2}-\frac{d}{t1})

Which for our values is:

v_w=\frac{1}{2}(\frac{400\ miles}{2.5h}-\frac{400\ miles}{4h})=30\ miles/h

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