Answer:
Part a)
![Reading = 2.00 kg](https://tex.z-dn.net/?f=Reading%20%3D%202.00%20kg)
Part b)
![Reading = 2.00 kg](https://tex.z-dn.net/?f=Reading%20%3D%202.00%20kg)
Part c)
![Reading = 4.04 kg](https://tex.z-dn.net/?f=Reading%20%3D%204.04%20kg)
Part d)
from t = 0 to t = 4.9 s
so the reading of the scale will be same as that of weight of the block
Then its speed will reduce to zero in next 3.2 s
from t = 4.9 to t = 8.1 s
The reading of the scale will be less than the actual mass
Explanation:
Part a)
When elevator is ascending with constant speed then we will have
![F_{net} = 0](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%200)
![T - mg = 0](https://tex.z-dn.net/?f=T%20-%20mg%20%3D%200)
![T = mg](https://tex.z-dn.net/?f=T%20%3D%20mg)
So it will read same as that of the mass
![Reading = 2.00 kg](https://tex.z-dn.net/?f=Reading%20%3D%202.00%20kg)
Part b)
When elevator is decending with constant speed then we will have
![F_{net} = 0](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%200)
![T - mg = 0](https://tex.z-dn.net/?f=T%20-%20mg%20%3D%200)
![T = mg](https://tex.z-dn.net/?f=T%20%3D%20mg)
So it will read same as that of the mass
![Reading = 2.00 kg](https://tex.z-dn.net/?f=Reading%20%3D%202.00%20kg)
Part c)
When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have
![F_{net} = ma](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20ma)
![T - mg = ma](https://tex.z-dn.net/?f=T%20-%20mg%20%3D%20ma)
![T = mg + ma](https://tex.z-dn.net/?f=T%20%3D%20mg%20%2B%20ma)
Reading is given as
![Reading = \frac{mg + ma}{g}](https://tex.z-dn.net/?f=Reading%20%3D%20%5Cfrac%7Bmg%20%2B%20ma%7D%7Bg%7D)
![Reading = 2.00\frac{9.81 + 10}{9.81}](https://tex.z-dn.net/?f=Reading%20%3D%202.00%5Cfrac%7B9.81%20%2B%2010%7D%7B9.81%7D)
![Reading = 4.04 kg](https://tex.z-dn.net/?f=Reading%20%3D%204.04%20kg)
Part d)
Here the speed of the elevator is constant initially
from t = 0 to t = 4.9 s
so the reading of the scale will be same as that of weight of the block
Then its speed will reduce to zero in next 3.2 s
from t = 4.9 to t = 8.1 s
The reading of the scale will be less than the actual mass
I believe C is your answer (also, I am also using tht same exact program!)
The correct answer to the question above is hypertonic. When celery is being placed in a glass of pure water, the solution inside its cells is going to appear as hypertonic compared to the water. This means that the cells inside has a higher concentration than outside.
The fourth dimension is technically time. the fourth dimension that you are talking about is actually impossible to comprehend.
The answers to your questions are as written below:
- The objects that represents a negatively charged particle is : Image B
- The object that represents a positively charged molecule is : Image A
- The object that represents an uncharged molecule is : Image C
- The object the will not move when in an electric fied is : Image C
<h3>Different types of charges molecules</h3>
A negatively charged molecule move inwards when placed in an electric field while positively charged molecule placed in a electric field will move outwards the electric field.
A neutral/uncharged molecule will remains still when placd in an elctric field due to the absence of charges.
Hence we can concude that the answers to your questions are as listed above.
Learn more about electric charges :brainly.com/question/857179
#SPJ4
attached below is the missing image