Answer:
-The speed of sound at 33°C is 362.8 m/s.
-The wavelength at a frequency at 5 kHz is 0.07256 m .
Explanation:
let v = 343 m/s be the speed of sound.
let T be the temperature.
then the speed of sound V, at 33°C is given by:
V = v + 0.6×T
= 343 + 0.6×33
= 362.8 m/s
Therefore, the speed of sound at 33°C is 362.8 m/s.
the wavelength at a frequency of f = 5kHz = 5000 Hz is given by:
λ = V/f
= (362.8)/(5000)
= 0.07256 m
Therefore, the wavelength at a frequency at 5 kHz is 0.07256 m .
Answer:
u= 187.61 ft/s
Explanation:
Given that
g= - 32 ft/s²
The maximum height ,h= 550 ft
Lets take the initial velocity = u ft/s
We know that
v²=u² + 2 g s
v=final speed ,u=initial speed ,s=height
When the object reach at the maximum height then the final speed of the object will become zero.
That is why
u²= 2 x 32 x 550
u²= 35200
u= 187.61 ft/s
That is why the initial speed will be 187.61 ft/s
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Answer:
percent decrease in power = 20 % .
Explanation:
Power P = v² / R where v is voltage and R is resistance which is constant .
taking log on both sides
log P = 2 log v - log R
differentiating on both sides
dP/P = 2 dv/v
-dP/P x 100 = 2 x -dv/v x 100
percent decrease in power = 2 x percent decrease in v ( voltage )
percent decrease in power = 2 x 10 = 20 %