All categories

3 years ago

What are the SI base units for length and mass?

Physics

2 answers:

notka56 [123]3 years ago

7 0

Answer:

meter and kilogram

Explanation:

As we know that there are seven fundamental SI units which are used to fine derived units

these are as following

1). Mass - Kilogram

2). Length - meter

3). Time - Seconds

4). Electric Current - Ampere

5). Amount of substance - Moles

6). Intensity of light - Candela

7). Temperature - Kelvin

hoa [83]3 years ago

6 0

The answer is:
Meter and Kilogram

I hope that i could be of assistance! ;)

You might be interested in

An object that is thrown straight up falls back to Earth. This is one-dimensional motion. (a) When is its velocity zero? (b) Doe

maw [93]

Answer:

Explanation:

(a) The velocity of object is zero when it is at maximum height.

(b) The direction of velocity changes as it starts moving downwards after it reaches the maximum height.

8 0

3 years ago

Read 2 more answers

A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob

andre [41]

Answer:

$I = -2.1 kg.m/s$

Explanation:

Given,

mass of the object,m = 0.30 Kg

initial speed, v_i = 3 m/s

time of collision = 0.20 s

final speed, v_f = -4 m/s

Impulse = change in momentum

$I = m (v_f-v_i)$

$I = 0.30\times (-4-3)$

$I = -2.1 kg.m/s$

Hence, impulse of the object is equal to $I = -2.1 kg.m/s$

5 0

3 years ago

In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l

QveST [7]

Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

$B=\dfrac{2\pi mf}{e}$

Where, f = frequency

e = charge of electron

Put the value into the formula

$B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}$

$B=0.077\ T$

(B). We need to calculate the energy of electron

Using formula of energy

$E=\dfrac{1}{2}m(r\omega)^2$

$E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2$

$E=1.4249\times10^{-16}\ J$

The energy in eV

$1 eV=1.6\times10^{-16}\ J$

$E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}$

$E=0.8906\ eV$

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

5 0

3 years ago

Can someone help me with this

yKpoI14uk [10]

bonded pairs of electrons, lone pairs of electrons.

4 0

3 years ago

A boy drops a ball from an observation tower. The ball hits the ground in 5.0 s. What is the ball's velocity at the time of impa

Orlov [11]

The answer is <span>C. 49 m/s

The kinetic equation is:
v2 = v1 + a * t

v1 - initial velocity
v2 - final velocity
a - gravitational acceleration
t - time

We know:
v2 = ?
v1 = 0 (in free fall
a = 9.8 m/s
t = 5

</span>v2 = v1 + a * t
v2 = 0 + 9.8 * 5
v2 = 0 + 49
v2 = 49 m/s

7 0

3 years ago