Answer:
nodding of head ,yes- static equilibrium
nodding of head, no- dynamic equilibrium.
Explanation:
static equilibrium monitors head position when body is not moving .
dynamic equilibrium monitors the angular or rotational movements of the head when body moves.
Answer:
3) C
4 D
5) C
Explanation:
3) given that
Initial distance of the screen = 100cm
Initial area = 150 cm^2
Final distance = 200 cm
The intensity of light is inversely proportional to the square of the distance. That is
Intensity of light I = 1/d2
And also I = P/A
1/d^2 = P/A
P = A/d^2
P1 = P2
150/100 = A/200
1.5 = A/200
A = 1.5 × 200
A = 300 cm^2
4.) Light is projected onto a screen 75.0 cm from a light source. The light intensity = 4436 lux
If the screen is moved from 75.0 cm to 150. cm, the light sensor reading will be
Using inverse square law
I = 1/d^2
I×d^2 = constant. Therefore,
4436 × 75^2 = I × 150^2
I = 24952500/22500
I = 1109 lux
5.) We can express the relationship between luminosity, brightness, and distance with a simple formula.
As we tilt the serene the area of light decreases and makes the light more concentrated.
Okay first you have to recognize that the maximum Gravitational potential energy will equal the maximum kinetic energy. The maximum GPE will equal when the stone is at its highest point and the max KE will be right before the stone hits the ground. So
GPE max = KE max
mgh = 1/2mv^2
Mass cancels as it is on both sides
gh = 1/2v^2
Multiply by 2
2gh = v^2
Square root
v = √2gh
Now plug in
v = √2(9.8)(4)
v = 8.85 m/s
Now use the mass to calculate the momentum just before it hits the ground as this is the speed right before it hits the ground
p = mv
p = (3)(8.85)
p = 26.55 kgm/s
Answer:
Change in Q = 2.1x 10^-3 C
Explanation:
We are given that
The Initialcapacitance C1 = 6.0μF
Initial charge oncapacitor
Q1 = C1 V
= 6.00 x 10^-6 x 100
= 6.00 x 10^-4 C
So the Final capacitance C2 will be
= K x C1 = 4.5 x 6.00 x 10^-6
= 2.7 x 10^ -5 F
So to get Finalcharge
We use Q2 = C2 x V
= 2.7 x 10^ - 5 x 100
= 27 x 10^ -4 C
So Charge flown in thecapacitor is change in Q
Which is = Q2 - Q1
= 27 x 10^-4 - 6.0 x 10^ -4
Change in Q = 2.1x 10^-3 C
Answer:
gravitational potantional energy
Explanation:
ill try to link a source!
edit: https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.3/primary/lesson/potential-energy-ms-ps#:~:text=Potential%20energy%20due%20to%20the,is%20called%20gravitational%20potential%20energy.
