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e-lub [12.9K]
3 years ago
14

In a perfectly inelastic one-dimensional collision between two objects, what condition alone is necessary so that the final kine

tic energy of the system is zero after the collision?
Physics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

In all types of inelastic collision we know that two objects move together with same speed after collision.

Now we know that in this type of collision energy is lost due to its permanent change in shape or size

Now when two objects will collide then the total momentum of the system will remains conserved as there is no external force on the system

So here we can say that

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_f

now we know that after collision if system comes to rest

then we will have

v_f = 0

m_1v_{1i} + m_2v_{2i} = 0

so here final kinetic energy is zero in all types of inelastic collision when the two objects have initial momentum zero during their motion

Crank3 years ago
5 0
<span>The condition alone that is necessary so that the final kinetic energy of the system is zero after the collision is that the objects must have momenta with the same magnitude but opposite directions.</span>
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A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit
DENIUS [597]

Answer:

the spear will end up above the fish relative to the actual position of the fish.

Explanation:

due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

So here we can say that the spear will end up above the fish relative to the actual position of the fish

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3 years ago
What are three (3) things you can do before exercise or sports that will keep you safe?
zaharov [31]

Answer: Drink water, practice, do some light stretches

Explanation:

3 0
3 years ago
You have a grindstone (a disk) that is 95.2 kg, has a 0.399 m radius, and is turning at 93 rpm, and you press a steel axe agains
olya-2409 [2.1K]

Answer:

angular acceleration is -0.2063  rad/s²

Explanation:

Given data

mass m = 95.2 kg

radius r = 0.399 m

turning ω = 93 rpm

radial force N  = 19.6 N

kinetic coefficient of friction  μ = 0.2

to find out

angular acceleration

solution

we know frictional force that is = radial force × kinetic coefficient of friction

frictional force = 19.6 × 0.2

frictional force = 3.92 N

and

we know moment of inertia  that is

γ =  I ×α = frictional force × r

so

γ  = 1/2 mr²α

α  = -2f /mr

α  = -2(3.92) /95.2 (0.399)

α  = - 7.84 / 37.9848 = -0.2063

so angular acceleration is -0.2063  rad/s²

3 0
3 years ago
Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the c
sladkih [1.3K]

Answer:

q₃ = -4.81 nC

Explanation:

We can use the Gauss Law here:

∅ = q/∈₀

where,

∅ = Net Flux = - 216 N.m²/C

q = total charge enclosed inside sphere = ?

∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²

Therefore,

- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²

q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)

q = - 1.91 nC

So, the total charge will be sum of all three charges:

q = q₁ + q₂ + q₃

- 1.91 nC = 1.74 nC + 1.16 nC + q₃

q₃ = - 1.91 nC - 1.74 nC - 1.16 nC

<u>q₃ = -4.81 nC</u>

5 0
2 years ago
Need help asap; put you as brainliest​
Vera_Pavlovna [14]

Answer:

unmmmmmmmm I think the answerA

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