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Inessa05 [86]
3 years ago
9

How to find all real solutions

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0
\bf \sqrt{\sqrt{x-5}+x}=5\leftarrow \textit{squaring both sides}
\\\\
\sqrt{x-5}+x=25\implies \sqrt{x-5}=25-x\leftarrow \textit{squaring both sides}
\\\\
x-5=(25-x)^2\implies x-5=625-50x+x^2
\\\\
0=x^2-51x+630\implies 0=(x-30)(x-21)

and surely you'd know what the roots are

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Here a = - 2 and r = 8 ÷ - 2 = - 4, thus

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