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Inessa05 [86]
3 years ago
9

How to find all real solutions

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0
\bf \sqrt{\sqrt{x-5}+x}=5\leftarrow \textit{squaring both sides}
\\\\
\sqrt{x-5}+x=25\implies \sqrt{x-5}=25-x\leftarrow \textit{squaring both sides}
\\\\
x-5=(25-x)^2\implies x-5=625-50x+x^2
\\\\
0=x^2-51x+630\implies 0=(x-30)(x-21)

and surely you'd know what the roots are

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Question 21 on this pictured math sheet please. Have a great day!
Yuki888 [10]

Answer:

39

Step-by-step explanation:

f(x) = 2x - 1.....(1) \\ g(x) = 3x + 5....(2) \\ plug \: x = 5 \: in \: (2) \\ g(5) = 3 \times 5 + 5 = 15 + 5 = 20 \\  \therefore \: f(g(5)) = 2 \times 20 - 1 = 40 - 1 = 39 \\  \\   \huge \red{ \boxed{\therefore \: f(g(5)) =39}}

7 0
3 years ago
Y=-2(×-3)(x-2) to standard form <br><br>(show work)​
damaskus [11]

Answer:

y=-2x^2+10x-12

Step-by-step explanation:

graph is shown in image below

4 0
2 years ago
A. 5°<br>B. 35°<br>C. 31°<br>D. 7°​
MrRissso [65]

Answer:

(2x +30) and (3x -5)  (they're opposite to eachother, so they're equal)

2x + 30 = 3x - 5 (set them equal to eachother, then subtract 3x from both side)

-1x = -35 (divide both sides by -1 to isolate x)

x = 35 or B (this is your answer)

Step-by-step explanation:

I hope this helps :))

3 0
3 years ago
Given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
Mamont248 [21]

Answer:

Step-by-step explanation:

From the given information:

a) To express the weekly profit as a function of price

Cost =C(q) = 1500 + 10q

Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²

Revenue = 50q - 0.1q²

Weekly profit = Revenue - Cost

P(q) = (50q -0.1q²) - (1500 + 10q)

P(q)= -0.1 q² + 40 q - 1500  

However, q = 500 - 10 p using p = 50 − 0.1q

P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500

P= -10 p² + 600 p - 6500

b)

The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0  

P' = 0

= -20p+600 = 0

20p = 600

p = 600/20

p = $30

c)

The maximum profit that can be made by the producer is:

P= -10(30)² + 600(30) - 6500

P = - 9000 + 18000 - 6500

P = $2500

5 0
3 years ago
N divided by 10 =32.7
sukhopar [10]
N/10 = 32,7
N = 32,7*10
N = 327
5 0
2 years ago
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