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Bess [88]
3 years ago
12

In a bag there are 10p coins, 20p coins and 50p coins

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer:

Approximately 25p (please change to pounds by yourself I'm not European, sorry).

Ok so according to my research its 100 pence to one pound. Which will mean that 25p in pounds is £ 00.25

Step-by-step explanation:

<h3>let's say:</h3><h3>10p= <em>x</em></h3><h3>20p=<em> </em><em>y</em><em> </em></h3><h3>50p= <em>z</em><em> </em></h3><h3>'3 fewer 20p (<em>y</em><em>)</em><em> </em>coins than 10p (<em>x</em>) coins'</h3><h3>Therefore:</h3><h3>y-3=<em>x</em><em> </em></h3><h3>and <em>y</em>= <em>x</em>+3</h3><h3>'7 more 50p coins (<em>z</em>) than 10p coins (<em>x</em>)'</h3><h3>That is:</h3><h3><em>z</em>+7= <em>x</em></h3><h3><em>z</em><em>=</em><em> </em><em>x-7</em></h3><h3>'altogether are 61 coins'</h3><h3><em>x</em><em>+</em><em>y</em><em>+</em><em>z</em><em> </em><em>=</em><em> </em>61 </h3><h3>(substitute for y and z)</h3><h3><em>x</em><em> </em>+ <em>x</em><em> </em>+ 3 + <em>x</em><em> </em>- 7 = 61</h3><h3><em>x</em><em>+</em><em>x</em><em>+</em><em>x</em><em>+</em><em>3</em><em>-7</em><em> </em><em>=</em><em> </em>61</h3><h3>3<em>x</em><em> </em>- 4= 61</h3><h3>3<em>x</em>= 61 + 4</h3><h3>3<em>x</em>=65</h3><h3><em>x</em>= 65÷3</h3><h3><em>x</em>= (approximately) 21.6 </h3><h3>(Substitute <em>x</em><em> </em>in <em>y</em><em> </em>and <em>z</em>)</h3><h3><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em>+</em>3</h3><h3><em>y</em><em> </em>= 21.6 + 3 = 24.6 (approximately 25)</h3><h3><em>z</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>-7</h3><h3><em>z</em><em>=</em><em> </em>21.6-7= 14.6 (approximately 15)</h3><h3>y= 20p </h3><h3>y= 25p (approximately)</h3><h3 /><h3><u>Check</u><u> </u></h3><h3>x+y+z= ?</h3><h3>21.6 + 24.6 + 14.6= 60.8 (approximately 61)</h3>

(Sorry I couldn't change to pounds)

And I tried to explain as much as possible, you can ask if you're confused.

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Answer:

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Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

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= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

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Answer:

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Step-by-step explanation:

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