Answer:
The acceleration of the rattlesnake, a = 126 m/s²
Explanation:
Given,
The initial velocity of the rattlesnake, u = 1.0 m/s
The final velocity of the rattlesnake, v = 20.0 m/s
The time duration to reach the final velocity, t = 0.15 s
The acceleration of a body defined as the rate of change of velocity by time, or simply the difference of final velocity and initial velocity by time.
The formula for acceleration is
a = (v-u)/t m/s²
Substituting the values in the above equation
a = (20 - 1.0 ) / 0.15
= 126 m/s²
Hence, the acceleration of the rattlesnake is, a = 126 m/s²
The correct option is d
<span>Weight changes depending on distance from the earth, mass does not.
Weight can be defined as the force exerted on an object due to the effects of gravity.
As we move far away from the Earth, the effects of gravity lessen and thus the weight decreases. (But the mass remains constant, because it only depends on the volume and density of the object)
</span>
Answer:
Number 6:
• From the formula of force:
• But we need to get the acceleration, from the first newtons equation of motion
• v is the final velocity, but v is zero because the bullet came to rest.
• u is the initial velocity, u = 350 m/s
• a is the acceleration that we need
• t is the time, t = 0.0018 seconds.
» let's now substitute:
[ negative shows retârdation or deceleration or decrease in speed ]
• Therefore, let's find the force:
mass = 6g = (6/1000) kg = 0.006 kg