1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tasya [4]
3 years ago
14

If the Sun were to stop shining, Earth would stop receiving heat and light within about eight minutes. Earth, however, would rem

ain habitable for days if not weeks MOSTLY because of heat A) from Earth’s mantle. B) from other nearby stars. C) stored in the Earth’s crust. D) stored in the atmosphere and oceans.
Physics
2 answers:
hjlf3 years ago
6 0
If<span> The </span>Sun<span> Went Out, How Long </span>Could<span> Life On </span>Earth<span> Survive? ... (which is actually physically impossible), the </span>Earth would stay<span> warm—at least ... from the planet's core </span>would<span> equal the</span>heat<span> that the </span>Earth<span> radiates into space, ... Photosynthesis </span>would<span> halt immediately, and </span>most<span> plants</span>would<span> die </span>in<span> a few </span>weeks<span>.</span>
vekshin13 years ago
3 0

im pretty sure the answer id D

You might be interested in
Someone help please.....
Westkost [7]

Answer:

0.0928km/min (4dp)

Explanation:

To find the jogger's speed in km per minute, we just need to divide the number of km jogged by the time in minutes it took to jog that distance. This will give us the distance they jogged every minute which is their speed.

4km in 32 minutes:

4/32 = 0.125km/min

2km in 22 minutes:

2/22 = 0.091 (3dp)km/min

1km in 16 minutes:

0.0625km/min

Now to find the average speed of these 3 speeds, we just add them all together and divide by how many values there are (3 values).

Average (mean)  = \frac{0.125+0.091+0.0625}{3}

Average = 0.2785/3

Average speed of jogger = 0.0928 (4dp) km/min

Hope this helped!

8 0
3 years ago
Your 64-cm-diameter car tire is rotating at 3.3 rev/swhen suddenly you press down hard on the accelerator. After traveling 250 m
umka21 [38]

Answer:

0.76 rad/s^2

Explanation:

First, we convert the original and final velocity from rev/s to rad/s:

v_o = 3.3\frac{rev}{s} * \frac{2\pi rad}{1rev} =20.73 rad/s

v_f = 6.4\frac{rev}{s} * \frac{2\pi rad}{1rev}=40.21 rad/s

Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:

D = x*r \\x = \frac{D}{r} = \frac{250m}{0.64m/2} = 781.25 rads

Now, we just use the formula:

w_f^2-w_o^2=2\alpha*x

\alpha =\frac{w_f^2-w_o^2}{2x} = \frac{(40.21rad/s)^2-(20.73rad/s)^2}{2*781.25rad} = 0.76 rad/s^2

6 0
3 years ago
Read 2 more answers
Diagram shows the velocity time graph for a particle moving in 16 seconds.
Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

  It is seen that the maximum change in velocity is at the time between 8s to 10s.

              Maximum acceleration: \frac{V}{t}

                                                    = \frac{20}{2}

                                                    = 10 m/s^{2}

b) The deceleration of the particle

          The velocity of particle is decreased after 10s so,

                     deceleration = - \frac{40}{6}

                                           = - 6.67 m/s^{2}

c)The total distance traveled by the particle = Area under the curve

                               = \frac{1}{2}* 4*20 + 4*20 +  \frac{1}{2}* 2*20+ 2*20+ \frac{1}{2}* 40*16

                                                       = 290 m

d)The average velocity of the particle = \frac{Area under the curve}{Total time}

                                                               = \frac{290}{16}

                                                               = 18.12 m/s

3 0
3 years ago
Please help . Anybody
Alona [7]

Answer:

1: c

2: a

3: b

sorry if I am wrong

6 0
3 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.00 mm. If a
ValentinkaMS [17]

Answer:

a. 11.5kv/m

b.102nC/m^2

c.3.363pF

d. 77.3pC

Explanation:

Data given

area=7.60cm^{2}\\ distance,d=2mm\\voltage,v=23v

to calculate the electric field, we use the equation below

V=Ed

where v=voltage, d= distance and E=electric field.

Hence we have

E=v/d\\E=\frac{23}{2*10^{-3}} \\E=11.5*10^{3} v/m\\E=11.5Kv/m

b.the expression for the charge density is expressed as

σ=ξE

where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2

If we insert the values we have

8.85*10^{-12} *11500\\1.02*10^{-7}C/m^{2}  \\102nC/m^{2}

c.

from the expression for the capacitance

C=eA/d

if we substitute values we arrive at

C=\frac{8.85*10^{-12}*7.6*10^{-4}}{2*10^{-3} } \\C=\frac{6.726*10^{-15} }{2*10^{-3} } \\C=3.363*10^{-12}F\\C=3.363pF

d. To calculate the charge on each plate, we use the formula below

Q=CV\\Q=23*3.363*10^{-12}\\ Q=7.73*10^{-12}\\ Q=77.3pC

8 0
4 years ago
Other questions:
  • Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?
    10·1 answer
  • What factors affect the speed of water waves
    6·1 answer
  • After using a thermometer where should it be placed
    11·1 answer
  • A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
    8·1 answer
  • What is the highest degrees above the horizon the moon ever gets during the year in the Yakima Valley ?
    6·1 answer
  • The number of mushrooms needed by a pizza restaurant is given by the
    6·1 answer
  • Which of the following would most likely produce the strongest magnetic
    10·1 answer
  • Please help me someone !
    13·1 answer
  • A flat (unbanked) curve on a highway has a radius of 220.0 m. A car rounds the curve at a speed of 25.0 m/s.
    11·1 answer
  • 1. As the angle of the ramp is increased, the normal force increases /decreases / remains the same and the friction-force increa
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!