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Tasya [4]
3 years ago
14

If the Sun were to stop shining, Earth would stop receiving heat and light within about eight minutes. Earth, however, would rem

ain habitable for days if not weeks MOSTLY because of heat A) from Earth’s mantle. B) from other nearby stars. C) stored in the Earth’s crust. D) stored in the atmosphere and oceans.
Physics
2 answers:
hjlf3 years ago
6 0
If<span> The </span>Sun<span> Went Out, How Long </span>Could<span> Life On </span>Earth<span> Survive? ... (which is actually physically impossible), the </span>Earth would stay<span> warm—at least ... from the planet's core </span>would<span> equal the</span>heat<span> that the </span>Earth<span> radiates into space, ... Photosynthesis </span>would<span> halt immediately, and </span>most<span> plants</span>would<span> die </span>in<span> a few </span>weeks<span>.</span>
vekshin13 years ago
3 0

im pretty sure the answer id D

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Which best describes a radioactive isitope
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The atoms that contain an unstable combination of neutrons and protons, or excess energy in their nucleus

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Shear stress created the San Andreas Fault in Southern California. It is an example of a _____.
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Shear stress created the San Andreas Fault in Southern California. It is an example of a <span>reverse fault.</span>
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Which best describes the act of using senses or tools to gather information
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The act of using senses or tools to gather information is called <em>Obser</em><em>vation</em><em>.</em>

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Aliens? do you believe?<br><br>To get the points go into detail :)
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Yes

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3 years ago
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engineers are using computer models to study train collisions design safer train cars. They start by modeling an elastic collisi
Archy [21]

Answer:

The final velocity of the second car is 57 m/s south.

Explanation:

This is an elastic collision between two train cars. In this case, the total kinetic energy between the two bodies will remain the same.

The formula to apply is :

m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f

where ;

m_1=mass of object 1\\v_1i=initial  velocity object1\\m_2=mass of object2\\v_2i=initial velocity object 2\\v_1f=final velocity object 1\\v_2f=final velocity object 2

Given in the question that;

m_1=14650kg\\v_1i=18m/s\\m_2=3825kg\\v_2i=11m/s\\v_1f=6m/s\\v_2f=?

Apply the formula as;

m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f

{14650*18}+{3825*11} = {14650 *6} + {3825 * v₂f}

263700+42075=87900 + 3825v₂f

305775 =87900 + 3825v₂f

305775-87900 = 3825v₂f

217875=3825v₂f

217875/3825 =v₂f

56.96 = v₂f

<u>57 m/s = v₂f { nearest whole number}</u>

4 0
2 years ago
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