Question

An object is moving at a velocity of 23 m/s. It accelerates to a velocity of 85 m/s over a time of 8.3 s. What acceleration did it experience?

Answer 1

$\frac{v \: final \: - v \: initial }{time} = \: a$
$\\ \frac{85 - 23}{8.3} = 7.467 \: \frac{m}{ {s}^{2} }$

Answer 2

Answer : It experience the acceleration is, $7.5m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 85 m/s

u = initial velocity  = 23 m/s

t = time = 8.3 s

a = acceleration = ?

Now put all the given values in the above equation 1, we get:

$85m/s=23m/s+a\times (8.3s)$

$a=7.5m/s^2$

Thus, it experience the acceleration is, $7.5m/s^2$