Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer: 45ft.
Step-by-step explanation:
Let assigned the value of x to the unknown lenght.
Therefore, the Length = xft
The with is 1/3 of the length and this. = 15ft.
Now , to get the length, we equate both together and then solve for x .
1/3 of x = 15
x/3 = 15
To get x, we multiply both side by 3
x = 45ft
The of the pool = 45ft.
Answer the answer is 25
Explanation:
Answer:
-35
Step-by-step explanation:
Since there are parentheses, you start with that. 3+4=7
Now, -5 x 7 =-35
