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snow_lady [41]
3 years ago
14

Which value of x is a solution of x < -2? A. -3 B. -2 C. -1 D. 0

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

-3<-2

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Lourdes has created the following challenges for you: She has given you three of the four points necessary to determine a rectan
BaLLatris [955]

Answer:

Plot each point, connect in the given order, add parallel line segments to those already there, take the coordinates of the intersection and record as answer.

a) (-1,3), (-1,2), (9,2)

  • Missing point is (9, 3)

b) (3,7), (5,7), (5,-3)

  • Missing point is (3, -3)

c) (-5,-5), (1,4), (4,2)

  • Missing point (-2, -7)

d) (-52,73), (96,73), (96,1483)

  • Missing point (-52, 1483)

<em>See attached</em>

5 0
3 years ago
Suppose a friend is having difficulty solving -2(q-5) &gt; -3(q+1). Explain how to solve the inequality, showing all the necessa
IgorC [24]

Firstly, use the distributive property of multiplication (A(B + C) = A×B + A×C) on -2(q - 5) and -3(q + 1): -2q+10>-3q-3

Next, apply the addition property of equality (whatever you add to one side you have to add the same quantity to the other), and add 3q on both sides: q+10>-3

Lastly, apply the subtraction property of equality (whatever you subtract on one side you have to subtract the same amount on the other side), and subtract 10 on both sides. <u>Your final answer will be q>-13</u>

8 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
3 years ago
S/4 -7 =9<br> any help solving this question?
sasho [114]

Answer:

S=64

Step-by-step explanation:

if the s is what your looking for

5 0
3 years ago
Read 2 more answers
6/9 written two different ways
Rashid [163]
6/9 is equivalent to the fractions 60/90 and 600/900. The amount of zeros you add on does not matter as long as you do it to the top and bottom. The division sign cancels it out.
5 0
3 years ago
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