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mash [69]
3 years ago
11

I NEED HELP THIS IS FROM MY HOMWORK DUE IN A HOUR

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer:

Increasing the speed of the particles

Explanation:

The energy absorbed in the phase B is used to increase the speed of the particles.

We can see a positive slope which shows that the temperature is increasing considerably with increasing time.

At this phase the reaction rate is become faster as the temperature change has a considerable effect on reaction rates.

Temperature is directly proportional to the average kinetic energy of reacting particles.

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5 0
4 years ago
Assume that the reaction for the formation of gaseous hydrogen fluoride from hydrogen and fluorine has an equilibrium constant o
Zina [86]

Answer:

The equilibrium concentrations of all species :

[H_2]= 0.314 M

[F_2]=0.314 M

[HF]=3.372 M

Explanation:

Moles of hydrogen gas = 3.00 mole

Concentration of hydrogen gas = [H_2]=\frac{3.00 mol}{1.5 L}=2.0 M

Moles of fluorine gas = 3.00 mole

Concentration of fluorine gas = [F_2]=\frac{3.00 mol}{1.5 L}=2.0 M

Given the equilibrium constant of the reaction = K_c=1.15\times 10^2

H_2(g)+F_2(g)\rightleftharpoons 2HF(g)

Initial

2.0 M  2.0 M     0

At equilibrium

(2.0-x)M  (2.0 -x)M         2x

An expression of K_c is given by :

K_c=\frac{[HF]^2}{[H_2][F_2]}

1.15\times 10^2=\frac{(2x)^2}{(2.0-x)(2.0 -x)}

On solving for x , we get :

x = 1.686 M

The equilibrium concentrations of all species :

[H_2]=(2.0 -1.686)M = 0.314 M

[F_2]=(2.0 -1.686)M = 0.314 M

[HF]=(2\times 1.686)M = 3.372 M

8 0
3 years ago
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4 years ago
There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g suc
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<span>0.5/1.75 = 0.285 M Hope this helps</span>
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Wittaler [7]
False.
It is expected to be 7.5, the mean of 7 and 10.
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