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maks197457 [2]
3 years ago
8

Which practice does the Montreal Protocol aim to reduce?

Chemistry
2 answers:
PolarNik [594]3 years ago
6 0
Ozone which is present in the stratospheric region of atmosphere is helpful for preventing harmful UV rays from reaching the surface of earth. Due to human activity, several compounds  (specifically chlorofluorocarbons) are released in atmosphere. Due to inherent chemical stability of these compounds, the remain stable in lower region of atmosphere and slowly diffuse into stratosphere. On reaching the stratosphere, these compounds reacts with ozone and thereby depletes the effective concentration of ozone present in atmosphere. Hence, <span>the Montreal Protocol was signed in 1987 by major countries of the world. This aim of this protocol was to protect the stratospheric ozone layer by phasing out the production and consumption of ozone-depleting substances.</span>
scZoUnD [109]3 years ago
6 0

Using CFCs is the answer, I just did it on --> (APEX)

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How are ionic compounds named?<br><br>​
Dimas [21]

Answer:

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Explanation:

For binary ionic compounds (ionic compounds that contain only two types of elements), the compounds are named by writing the name of the cation first followed by the name of the anion.

4 0
3 years ago
n acid with a pKa of 8.0 is present in a solution with a pH of 6.0. What is the ratio of the protonated to the deprotonated form
Nady [450]

Answer : The ratio of the protonated to the deprotonated form of the acid is, 100

Explanation : Given,

pK_a=8.0

pH = 6.0

To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}

Now put all the given values in this expression, we get:

6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}

\frac{[Deprotonated]}{[Protonated]}=0.01  

As per question, the ratio of the protonated to the deprotonated form of the acid will be:

\frac{[Protonated]}{[Deprotonated]}=100  

Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100

5 0
3 years ago
Can somebody help me plz
xxMikexx [17]

Answer:r=1.2 d=2.4

Explanation:

Radius is half the diameter and the diameter is 2.4 m

8 0
3 years ago
Read 2 more answers
What is radius? When might you need to measure an object’s radius?
katrin2010 [14]
It’s halfway into the circle, you would need it when trying to find the circumference
3 0
3 years ago
Which of the statements correctly describes the reactivity of halogens, according to the octet rule?
zzz [600]
They have seven electrons in their valence shell, so halogens are very reactive.
Hope this helps! :)
8 0
3 years ago
Read 2 more answers
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