Answer:
14 moles of CO are needed in the reaction, to react with 7 moles of O₂
Explanation:
We need to determine the reaction to start:
O₂ (g) + 2CO (g) → 2CO₂ (g)
Now, we state the ratio of reactants:
1 mol of oxygen needs 2 moles of CO, to react and they both, produce 2 moles of CO₂. Therefore the ratio is 1:2
We can make a rule of three to reach the answer:
1 mol of O₂ needs 2 moles of CO to react
Therefore, 7 moles of O₂ must need (7 .2) /1 = 14 moles
Answer:
B. Nuclear fission reactions use only a small amount of material to
produce a large amount of energy.
C. Nuclear reactors use controlled reactions.
Explanation:
Nuclear reactors are devices that contain and control nuclear chain reactions while releasing heat produced from these nuclear chain reactions at a controlled rate.
A nuclear power plant uses the enormous amount of heat that are produced from the nuclear chain reactions occurring in the nuclear reactor to turn water into steam, which then drives turbine generators that generate electricity.
The nuclear chain reactions occurring in the nuclear reactor are fission chain reactions. A nuclear fission reaction is a reaction in which a larger atom is split into two or more smaller atoms when bombarded with energetic neutrons resulting in the release of large amounts of energy and more neutrons. The neutrons released split more atoms of the larger atom into smaller atoms in what is known as a chain reaction. This reaction is controlled by means of moderators. A moderator helps slow down the neutrons produced by fission to sustain the chain reaction.
The molar mass of nitrogen is 14.0067amu or just 14amu.
Answer:
It kinda is
Explanation:
The school system isn't very affective on the young adolcent minds, the crime rate is very high (indicating poverty rates) some drug smmuglers are based in Haiti, and half the city is destroyed from either people or the environment.
Answer:
4.48 grams of potassium hydroxide that the chemist must be weighing out.
Explanation:
The pH of the KOH solution = 13
pH + pOH = 14
pOH = 14 - pH = 14 - 13 = 1
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
![1=-\log[OH^-]](https://tex.z-dn.net/?f=1%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=0.1 M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.1%20M)
1 mole of hydroxide ions are obtained from 1 mole of KOH. Then 0.1 mole of hydroxide ions will be obtained from :
of KOH
![[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}](https://tex.z-dn.net/?f=%5BMolarity%5D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%7D%7D%7B%5Ctext%7BVolume%20of%20solution%28L%29%7D%7D)
Volume of KOH solution = 800 mL = 0.800 L ( 1 mL = 0.001 L)
Moles of KOH = 0.1 M × 0.800 L = 0.08 mol
Mass of 0.08 moles of KOH :
0.08 mol × 56 g/mol = 4.48 g
4.48 grams of potassium hydroxide that the chemist must be weighing out.
