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3 years ago

An antacid tablet contains 640.0 mg of magnesium oxide per tablet.

Chemistry

1 answer:

Salsk061 [2.6K]3 years ago

3 0

Answer:

317.6 mL

Explanation:

Step 1: Write the balanced neutralization equation

MgO + 2 HCl ⇒ MgCl₂ + H₂O

Step 2: Calculate the mass corresponding to 640.0 mg of MgO

The molar mass of MgO is 40.30 g/mol. The moles corresponding to 640.0 mg (0.6400 g) of MgO are:

0.6400 g × (1 mol/40.30 g) = 0.01588 mol

Step 3: Calculate the moles of HCl that react with 0.01588 moles of MgO

The molar ratio of MgO to HCl is 1:2. The moles of HCl are 2/1 × 0.01588 mol = 0.03176 mol

Step 4: Calculate the volume of 0.1000 M HCl that contains 0.03176 moles

0.03176 mol × (1 L/0.1000 mol) = 0.3176 L = 317.6 mL

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A plastic bin is found to hold 3.1x10^24 molecules of water.

motikmotik

Answer:

$\boxed {\boxed {\sf 5.1 \ mol \ H_2O}}$

Explanation:

To convert from representative particles to moles, Avogadro's Number: 6.02*10²³, which tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance.

We can use it in a ratio.

$\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}$

Multiply by the given number of molecules.

$3.1*10^{24} \ molecules \ H_2O*\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}$

Flip the ratio so the molecules of water cancel out.

$3.1*10^{24} \ molecules \ H_2O*\frac {1 \ mol \ H_2O}{6.02*10^{23} \ molecules \ H_2O}$

$3.1*10^{24} *\frac {1 \ mol \ H_2O}{6.02*10^{23} }$

$\frac {3.1*10^{24} \ mol \ H_2O}{6.02*10^{23} }$

Divide.

$5.14950166113 \ mol \ H_2O$

The original number of molecules has 2 significant figures: 3 and 1, so our answer must have the same. For the number we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.

$5.1 \ mol \ H_2O$

There are about 5.1 moles of water in 3.1*10²⁴ molecules of water.

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2 years ago

4. What is the volume of a 25% methyl solution that contains 20mL of methyl?

Akimi4 [234]

25% of 20
%=100
25/100 x 20
1/4 x 20
The answer is equal to 5

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3 years ago

Read 2 more answers

HELP Which of the following fractions can be used in the conversion of 32 m3 to the unit mm3?

poizon [28]

We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m

We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
1 mm³ = (10⁻³)³ m³

Therefore, the conversion used will be:
(1 mm / 10⁻³ m)³

When we multiply by this conversion, we will get:
32 m³ = 32 x 10⁹ mm³

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3 years ago

The mass of an electron is about 9.11 × 10 -9 kg., write this whole number

Pepsi [2]

Answer:0.00000009

Explanation:

9.11 × （1/1000000000）=0.00000009

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2 years ago

Si 100 monedas tienen una masa total de 226.13g. Cual es la masa de una moneda

galben [10]

The mass of a coin : 2.2613 g

<h3>Further explanation </h3>

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

1. phrases

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

2. variables

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

3. constants

is a fixed value, can be a number

4. arithmetic operations ⇒ +, - , : , x

<em>If 100 coins have a total mass of 226.13g. What is the mass of a coin</em>

We can make this statement in the form of an algebraic equation :

100 coins=226.13 g

then the mass of a coin :

$\tt \dfrac{1}{100}\times 226.13~g=2.2613~g$

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3 years ago