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julsineya [31]
3 years ago
10

a helium balloon containing 12m³ of gas at a pressure of 120kPa is released into the air. Assuming that the temperature is const

ant, calculate the volume of the balloon would have when the pressure inside the balloon has fallen to 40kPa, answer in m³
Physics
2 answers:
love history [14]3 years ago
4 0

Answer: 36m3

Explanation:

erik [133]3 years ago
4 0

Answer:

Explanation:

Eaton very cab

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Mathematically, explain how a car (A) with mass of 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with ma
scoray [572]

Answer:

<em>Both kinetic energies are equal</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed of the object

The kinetic energy is expressed in Joules (J)

There are two cars:

Car (A) with mass ma=500 kg and speed va= 2 m/s

Car (B) with mass mb=20,000 gr and speed vb= 10 m/s

Calculate the kinetic energy of both cars:

\displaystyle K_a=\frac{1}{2}m_av_a^2

\displaystyle K_a=\frac{1}{2}500*2^2

\displaystyle K_a=250*4=1,000 J

To calculate the Kb, the mass must be expressed in kg:

mb=20,000/1,000 =20 Kg

\displaystyle K_b=\frac{1}{2}m_bv_b^2

\displaystyle K_b=\frac{1}{2}20*10^2

\displaystyle K_b=10*100=1,000 J

Both kinetic energies are equal

8 0
3 years ago
Pls help thank you ​
DENIUS [597]

Punching a bag is a suitable example of the situation when the force applied to change shape of an object.

7 0
2 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
An image cannot be projected and forms where light rays appear to originate.
irakobra [83]

An VIRTUAL image cannot be projected, and

forms where light rays appear to originate.

3 0
3 years ago
The equation of a wave is represented by: Y = 0.005sin 2π(0.5x – 200t) where x and y are in meters and t in seconds. Find its i.
lys-0071 [83]

Answer:

See solution below

Explanation:

The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)

A is the amplitude

λ is the wavelength

f is the frequency

t is the time

Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)

i) A = 0.005m

Amplitude is 0.005m

ii) ω = 2πf

ω = 2π(200)

ω = 400π rad/s

iii) ω = 2πf

400π = 2πf

200 = f

Swap

f = 200Hertz

iv) Period = 1/f

Period = 1/200

Period = 0.005secs

v) wave number  =

vi) Wavelength λ

0.5x = x/λ

0.5 = 1/λ

λ  = 1/0.5

λ = 2m

vii) velocity - fλ

velocity = 200 * 2

velocity = 400m/s

7 0
3 years ago
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