Pls help thank you
1 answer:
You might be interested in
There are mistakes in the question.The correct question is here
A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntable’s angular velocity, in rpm, just after this event?
Answer:
w=50 rpm
Explanation:
Given data
The mass turntable M=2kg
Diameter of the turntable d=20 cm=0.2 m
Angular velocity ω=100 rpm= 100×(2π/60) =10.47 rad/s
Two blocks Mass m=500 g=0.5 kg
To find
Turntable angular velocity
Solution
We can find the angular velocity of the turntable as follow
Lets consider turntable to be disk shape and the blocks to be small as compared to turntable
where I is moment of inertia
Answer:
<em>The radius of the balloon is R= 0.974 m</em>
Explanation:
Atmospheric density on the surface of mars ρ = 0.0154 kg/m³
Mass density of balloon σ 5 gm/m² = 0.005 kg/m²
Total mass of balloon M = density of balloon* surface area
The balloon is considered as sphere
Surface area of sphere is given by 4π R²
Mass of balloon is M =σ *4πR²
M= (0.005 kg/m²)*(4π R²)
Volume of balloon is given by πR³
Density of atmosphere of mass is given by
ρ = Mass of balloon/volume of balloon
=(0.005 kg/m²)*(4π R²)/ πR³
Re arranging R
R =
R = 0.974 m
<em>The radius of the balloon is R= 0.974 m</em>
<em></em>