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maksim [4K]
2 years ago
5

Is the magnitude of the acceleration of the center of mass of spool A greater than, less than, or equal to the magnitude of the

acceleration of the center of mass of spool B?

Physics
1 answer:
Anon25 [30]2 years ago
6 0

Answer:

The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.

Explanation:

From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.

And for the acceleration of both spools, we mention the net force.

The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.

For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.

With the net force and mass, for each spool equal, from

ΣF = ma, we get that a = ΣF/m

Meaning that the acceleration of the identical spools is equal also.

Hope this Helps!

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Which set of atoms will form an ionic compound?
Oksanka [162]

Answer:

The answer is A)

Explanation:

An ionic compound is formed when one atom donates one or more electrons to one or more atoms of another element. Calcium has two valence electrons, which are donated to an atom of oxygen. So, an ionic compound is formed in the reaction involving one calcium atom with an oxygen atom.

8 0
3 years ago
if an object is falling on earth at a terminal velocity of 140 km/hr, does that mean that the acceleration is ZERO?
Simora [160]
If he's falling in a straight line and his speed is not changing, that tells you that his acceleration is zero.

And THAT tells you that the forces on him are balanced, the net force acting on him is zero, and his motion is the same as it would be if there were NO force acting on him.
7 0
3 years ago
You are to design a rotating cylindrical axle to lift 800-N buckets of cement from the ground to a rooftop 78.0 m above the grou
Ronch [10]

Answer:

The diameter of the axle is 5.08 cm.

Explanation:

Given that,

Force = 800 N

Distance = 78.0 m

Suppose we need to find the diameter of the axle be in order to raise the buckets at a steady 2.00 cm/s when it is turning at 7.5 rpm.

We need to calculate the radius of axle

Using formula of linear velocity

v = r\omega

r=\dfrac{v}{\omega}

Where, v =velocity

r = radius

\omega=angular velocity

Put the value into the formula

r=\dfrac{2.00}{7.5\times\dfrac{2\pi}{60}}

r=2.54\ cm

We need to calculate the diameter of axle

Using formula of diameter

d=2r

d=2\times2.54

d=5.08\ cm

Hence, The diameter of the axle is 5.08 cm.

8 0
3 years ago
A golf ball is hit with an initial velocity of 155 ft/s at an angle of 23 degrees with the horizontal. After 1.4 seconds, how fa
riadik2000 [5.3K]

<span>2) s(t) = 155tcos(23°) </span>
<span>=> s(1.4) = 155 * 1.4 * cos(23°) </span>
<span>=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally </span>

<span>a(t) = -32 ft/s^2 </span>
<span>=> v(t) = -32t + 155sin(23°) </span>
<span>=> h(t) = -16t^2 + 155tsin(23°) </span>
<span>=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°) </span>
<span>=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.</span>
6 0
2 years ago
A comet passes Earth over its equator. Pictures are taken of it from Earth's north and south poles simultaneously. In these pict
jok3333 [9.3K]

Answer:

Option B. 1,100 Earth diameters

Solution:

Angular position of steroid, \theta = 0.05^{\circ} = 8.726\times 10^{-4} radians                           (given)

To calculate the distance of asteroid, we use parallax method given as:

\theta = \frac{arc length(l)}{radius(R)}                 (1)

where,

From the relation:

l = \theta \times R

we get:

distance(d) or R = \frac{Earth diameter}{\theta}

distance(d) or R = \frac{2\times radius of earth}{\theta}

d = \frac{2\times 6350000}{8.726\times 10^{-4}}

distance, d = 1.455\times 10^{10} m

Comparing it with Earth's diameter:

d = \frac{1.455\times 10^{10}}{2\times 6350000} = 1,146

Since, the value is close to 1,100 Earth diameters, therefore, option B is the right answer.

4 0
3 years ago
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