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3 years ago

What the value of b?

Mathematics

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:

Hope it helps you!...........

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A water tank holds 621 gallons but is leaking at a rate of 4 gallons per week. A second water tank holds 828 gallons but is leak

hram777 [196]

Answer:

69 weeks

Step-by-step explanation:

Let the number of weeks be x.

The first tank holds 621 gallons is leaking at a rate of 4 gallons per week. This means that after x weeks, the amount of water in the tank is:

621 - 4x

The second tank holds 828 gallons is leaking at a rate of 7 gallons per week. This means that after x weeks, the amount of water in the tank is:

828 - 7x

After a certain amount of weeks, the amount of water in both tanks is the same. That means that:

621 - 4x = 828 - 7x

=> 7x - 4x = 828 - 621

3x = 207

x = 207 / 3 = 69

This means that the amount of water in the tank will be the same after 69 weeks.

8 0

4 years ago

Solve for m. 9 = m/10

deff fn [24]

HOPE THIS WILL HELP YOU.....

6 0

4 years ago

Read 2 more answers

PLEASE HELPPP!!! THANK YOU SOO MUCH ILY!!!!!!!

MissTica

Answer:

1) Variables = 11a , 4a

Constants = 0

Coefficients = 11 , 4

2) Variables = 3x , 7x

Constants = 6 , -4

Coefficients = 3 , 7 , 6 , -4

3) Variables = -12m , +4m

Constants = -3 , 16

Coefficients = -12 , 4 , -3 , 16

4) Variables = 6k , k

Constants = -4 , -2

Coefficients = 6 , 1 , -4 , -2

5) Variables = -5p , -2p

Constants = 3 , 13

Coefficients = -5 , -2 , 3 , 13

6) Variables = -10r , -r , -6r

Constants = 11

Coefficients = -10 , -1 , -6 , 11

7) Variables = -5n

Constants = 19 , -8 , 14

Coefficients = -5 , 19 , -8 , 14

8) Variables = 13y , -2y

Constants = 18 , -5

Coefficients = 13 , -2 , 18 , -5

9) Variables = 8a , 3a , -7b , -2b

Constants = 1

Coefficients = 8 , 3 , -7 , -2 , 1

10) Variables = 11x , 2x , -4y

Constants = 8

Coefficients = 11 , 2 , -4 , 8

Step-by-step explanation:

8 0

3 years ago

What percent is... 50% of 50% of x

tangare [24]

It’s 25%...........

3 0

3 years ago

I’m so confused. Need the help

fomenos

1.621 kN

Step-by-step explanation:

Let the centerline of the canal be the x-axis. Because the forces exerted by the horses are symmetric to the centerline, only the x-components of these forces contribute to the resultant force on the barge, i.e., the y-components cancel out. Each x-component is equal to $F_x = 839\cos 15$ = 810.4 N. Therefore, the resultant force on the barge is twice this:

$F_{net} = 2(839\:\text{N})\cos 15 = 1620.8\:\text{N}$

$= 1.621\:\text{kN}$

6 0

3 years ago