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satela [25.4K]
2 years ago
10

Please helppppppppppp i put it at 50 points-

Mathematics
2 answers:
AleksandrR [38]2 years ago
4 0
When rob sells 60-70 whatever I hope this helps
Mekhanik [1.2K]2 years ago
4 0

Answer:

98

Step-by-step explanation:

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If 4 notebooks and 3 packages of pens cost $7.43 and
SashulF [63]

Answer:

i believe its one of these!

A. $0.89 B.$0.79 C. $1.29

Step-by-step explanation:

6 0
2 years ago
Which of the following equations is an example of inverse variation between
Romashka [77]

For this case we have that by definition, a direct variation is given by:

y = kx

Where:

k: It is the constant of proportionality of the variables.

On the other hand, we have that the inverse variation is given by:

y = \frac {k} {x}

Where:

k: It is the constant of proportionality of the variables.

In this way, the correct option is: y = \frac {9} {x}

ANswer:

Option A

3 0
2 years ago
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80 houses are build 50 have 2 car garage 40 have swimming pool and 35 have bouth how much have none
kow [346]
30 should be the correct answer
 
4 0
3 years ago
If f(x) = 3x2 + 1 and g(x) = 1 - X, what is the value of (f – 9)(2)?
bezimeni [28]
The answer is 36 because you have to multiply it and divide getting your the answer.
4 0
3 years ago
Read 2 more answers
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
2 years ago
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