Please helppppppppppp <br><br><br><br> i put it at 50 points-

bezimeni [28]

Answer:

1. 144 2. 16 3. 1 4. 3x-6

Step-by-step explanation:

So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).

Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]

so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)

So take the h(x) function which is h(x) = $x^{2}$ then h(12) = $12^{2}$ so h(12) = 144

4 0

3 years ago

A ball is dropped from a certain height. The function below represents the height f(n), in feet, to which the ball bounces at th

Vladimir [108]

The answer is C hope I helped

6 0

3 years ago

Which sequence represents an arithmetic sequence?

Sergio039 [100]

we know that

arithematic sequence will always have common difference

(a)

−5, −7, −10, −14, −19, …

we can see that

$d_1=-7+5=-2$

$d_2=-10+7=-3$

they are not equal

so, this is not arithematic sequence

(2)

1.5, −1.5, 1.5, −1.5, …

we can see that

$d_1=-1.5-1.5=-3$

$d_2=1.5+1.5=3$

they are not equal

so, this is not arithematic sequence

(3)

4.1, 5.1, 6.2, 7.2, …

we can see that

$d_1=5.1-4.1=1$

$d_2=6.2+5.1=1.1$

they are not equal

so, this is not arithematic sequence

(4)

−1.5, −1, −0.5, 0, …

we can see that

$d_1=-1+1.5=0.5$

$d_2=-0.5+1=0.5$

they are equal

so, this is arithematic sequence

8 0

4 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

3 years ago

Read 2 more answers

Jason and Kyle both choose a number from 1 to 10 at random. What is the probability that both numbers are odd?

Artemon [7]

Your answer is

B) 1/2

because there are 5 odd and 5 even numbers from 5 through 10, so it would be 1/2.

Glad I could help, and good luck!

4 0

4 years ago

Read 2 more answers

Please helppppppppppp i put it at 50 points-