Answer:
- Son buenos conductores de electricidad.
- Excelentes conductores de calor.
- Tienen una alta tenacidad.
- Se encuentran en estado solido, exepto por el mercurio.
- Y se destaca la baja electronegatividad.
Sorry my drawings aren’t great, but I hope this helps
All of the above (hope that helps!)
Answer:
T = 20.42 N
Explanation:
given data
standard altitude = 30,000 ft
velocity Ca = 500 mph = 0.4 m/s
inlet areas Aa = 7 ft² = 0.65 m²
exit areas Aj = 4.5 ft² = 0.42 m²
velocity at exit Cj = 1600 ft/s = 487.68 m/s
pressure exit
j = 640 lb/ft² = 0.3 bar
solution
we get here thrust of the turbojet that is express as
thrust of the turbojet T = Mg × Cj - Ma × Ca + (
j Aj -
a Ag ) .............1
here Ma = Mg
Ma =
a × Ca Aa = 0.042 kg/s
put value in equation 1 we get
T = 0.042 × (487.68 -0.14) + ( 0.3 × - 0.3 × 0.65 )
T = 20.42 N
Answer:
Hello your question is incomplete attached below is the complete question
answer:
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )
Explanation:
attached below is the detailed solution
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )