Determine an expression in standard form for the voltage gain VoVs. Hv(jω)=Vo(jω)Vi(jω)=R2R111+jωCR2 Hv(jω)=Vo(jω)Vi(jω)=−R2R111
+jωCR2 Hv(jω)=Vo(jω)Vi(jω)=−R2R111−jωCR2 Hv(jω)=Vo(jω)Vi(jω)=−R1R211+jωCR2 HintsReferenceseBook & Resources Hint #1
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Answer:
a) 180 m³/s
b) 213.4 kg/s
Explanation:
= 1 m²
= 100 kPa
= 180 m/s
Flow rate
Volumetric flow rate = 180 m³/s
Mass flow rate
Mass flow rate = 213.4 kg/s