Answer:
74.12kg/day
Explanation:
Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O
Mass of sulfuric acid produced per day = 90,800kg
Percentage of sulfuric acid in wastewater = 0.1%
Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg
From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)
80kg of NaOH is required to neutralize 98kg of sulfuric acid
90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH
Answer:B
Explanation:
Given
For motor A
Characteristic life(r)=4100 hr
MTTF=4650 hrs
shape factor(B )=0.8
For motor B
Characteristic life(r)=336 hr
MTTF=300 hr
Shape Factor (B)=3
Reliability for 100 hours
For B
B is better for 100 hours
(b)For 750 hours
So here B is more Reliable.
Answer: Technician A
Reason: Piston and rod are connected with crank shaft and connecting rod. Smaller end of connecting rod is connected with piston and bigger end is connected with crankshaft.
<u>Explanation:
</u>
When removing the piston and rod assemblies from a cylinder block: The technician with correct approach. So to remove piston from cylinder technician must throw crankshaft first and the remove connecting rod by losing nuts and caps...So technician A is in right way. Technician B using hammer to remove piston from the rod not possible because connecting rod and piston connected by nuts and caps can’t be separate by hammer.
Technician A positions the throw of the crankshaft at the top of its stroke and removes the connecting rod nuts and cap.
Technician B covers the rod bolts with hammers and pushes the piston and rod assembly out with the wooden hammer handle or wooden drift and supports the piston as it comes out of the cylinder.
option 2 is your answer... thanks .. hope it helps
