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3 years ago

What is government role in the modern American version of capitalism

Engineering

1 answer:

Mademuasel [1]3 years ago

5 0

Answer:

Capitalism is an economic system.

Explanation:

Capitalism is an economic system based on the private ownership of the means of production and their operation for profit.

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A plane wall of length L, constant thermal conductivity k and no thermal energy generation undergoes one-dimensional, steady-sta

KIM [24]

Answer:

Temperature distribution is $T(x)=\dfrac{q}{k}(L-x)+T$

Heat flux=q

Heat rate=q A

Explanation:

We know that for no heat generation and at steady state

$\dfrac{\partial^2 T}{\partial x^2}=0$

$\dfrac{\partial T}{\partial x}=a$

$T(x)=ax+b$

a and are the constant.

Given that heat flux=q

We know that heat flux given as

$q=-K\dfrac{dT}{dx}$

From above we can say that

$a= -\dfrac{q}{K}$

Alos given that when x= L temperature is T(L)=T

$T= -\dfrac{q}{K}L+b$

$b=T+\dfrac{q}{K}L$

So temperature T(x)

$T(x)=-\dfrac{q}{K}x+T+\dfrac{q}{K}L$

$T(x)=\dfrac{q}{k}(L-x)+T$

So temperature distribution is $T(x)=\dfrac{q}{k}(L-x)+T$

Heat flux=q

Heat rate=q A (where A is the cross sectional area of wall)

6 0

3 years ago

Sedimentary rock forms at or near the

Natalija [7]

I believe it’s A bit I. could be wrong

5 0

3 years ago

Read 2 more answers

We are undergoing a period of rapid technology change with cloud computing, artificial intelligence, robotics, mobile devices, w

Law Incorporation [45]

2 cause this shot gas

3 0

3 years ago

Question 5 1 pts Lumber which has been put through a planer is known as surfaced or ]

Naddik [55]

Answer:

what does that mean welp I have no idea sorry for answering

8 0

3 years ago

Consider a single bacterial cell as a discrete particle with a diameter of 1x10-6m and a specific gravity of 1.01. Assuming lami

Alinara [238K]

Answer:

Sedimentation is not a good method.

Explanation:

We need to apply Stoke laws and assume that is valid here.

So,

$V_s= 418(G-1)d^2(\frac{3T+70}{100})$

Replacing the values,

$V_s= (418)(1.01-1)(10^-3)^3*(\frac{3*20+70}{100})\\V_s=5.434*10^-6mm/s$

Here then we calculate the time,

$t_{req}=\frac{x}{v}$

Where x= Distance, v= velocity

$t_{req}=\frac{1foot}{5.434*10^{-6}} = \frac{304.8}{5.434*10^{-6}}\\t_{req}=649.2days$

To calculate the surface required we need first to calculate the volume through the volume,

So,

$Q=4MGD=4*10^6*0.135 (ft^3/day)$

Then,

$V_{req} = Q*t\\V_{req}=4*10^6*0.134*649.2\\V_{req}=34.79*10^7ft^3$

Here we can calculate the surface

$S_{req}= \frac{Volume}{Distance}=\frac{34.79*10^7}{1}\\S_{req}=7987.8 Acres$

So, the requeriment of Area of tank and settlement time is huge, it's not a practical method.

6 0

3 years ago