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3 years ago

A solution is made by dissolving

Chemistry

1 answer:

AVprozaik [17]3 years ago

5 0

Answer:

0.342 m

Explanation:

From the question given above, the following data were obtained:

Mass of NaBr = 14.57 g

Mass of water = 415 g

Molar mass of NaBr = 102.89 g/mol

Molality of NaBr =?

Next, we shall determine the number of mole in 14.57 g of NaBr. This can be obtained as follow:

Mass of NaBr = 14.57 g

Molar mass of NaBr = 102.89 g/mol

Mole of NaBr =?

Mole = mass / molar mass

Mole of NaBr = 14.57 / 102.89

Mole of NaBr = 0.142 mole

Next, we shall convert 415 g of water to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

415 g = 415 g × 1 Kg / 1000 g

415 g = 0.415 Kg

Thus, 415 g is equivalent to 0.415 Kg.

Finally, we shall determine Molality of the solution as follow:

Mole of NaBr = 0.142 mole

Mass of water = 0.415 Kg

Molality of NaBr =?

Molality = mole / mass of water in Kg

Molality of NaBr = 0.142 / 0.415

Molality of NaBr = 0.342 m

Therefore, the molality of NaBr solution is 0.342 m.

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If the statement is true, select True. If it is false, select False.

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Answer:

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The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilo

Lynna [10]

Answer:

NA = 6.8 E-12 Kg H2(g) / hour

Explanation:

steady-state diffusion of A through non-diffuser B:

NA = (DAB/RTz)(p*A1 - p*A2)

∴ (A): H2(g)

∴ (B): Pd

∴ DAB = 1.7 E-8 m²/s

∴ p*A1 = 2.0 Kg H2 / m³ Pd

∴ p*A2 = 0.4 Kg H2 / m³ Pd

∴ z = 6 mm = 6 E-3 m

∴ T = 600°C ≅ 873 K

∴ R = 8.314 J/mol.K = 8.314 N.m/mol.K

⇒ NA = ((1.7 E-8)/(8.314)(873)(6 E-3))(2.0 - 0.4)

⇒ NA = 6.246 E-10 mol/s.m³

for A = 0.25 m²

⇒ volume (v) = A×z = (0.25)(6 E-3) = 1.5 E-3 m³

∴ Mw H2(g) = 2.016 g/mol

⇒ NA = (6.246 E-10 mol/s.m³)(1.5 E-3 m³)(2.016 g/mol)(Kg/1000 g)(3600 s/h)

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3 years ago

__N2O5+__H2O->__HNO3 <br><br> What's the reaction?

77julia77 [94]

Answer:

N₂O₅ + H₂O --> 2HNO₃

This reaction is a combination reaction

Explanation:

I find that making a table is an easy way to balance a table. The table would be something like this:

Reactants (left) Products (right)

N = 2 N = 1

O = 6 O = 3

H = 2 H = 1

The number next the symbol represents how many of atoms of that particular element are present.

The aim is to make the number of atoms of each element on the left side to be equal to the number of atoms of each element on the right side. As we can see, there are 1 more nitrogen than on the right, 3 more oxygen than on the right and 1 more hydrogen than on the left.

So to make the numbers of atoms of each element on right equal to the number of atoms of each element on the left, we have to add a number. This number CANNOT be a subscript number because that would change the reaction.

We can add a 2 in front of the product (this is because there are less atoms in the right side of the equation).

N₂O₅ + H₂O --> 2HNO₃

This means there are now two HNO₃ molecules so every atom in this molecule is basically multiplied by 2. So 1 nitrogen atom becomes two (1 × 2 = 2), 3 oxygen atoms become 6 (3 × 2 = 6) and 1 hydrogen atom becomes 2 (1 × 2 = 2). If we were to make a table again with the following equation - N₂O₅ + H₂O --> 2HNO₃, the table would be as so:

Reactants (left) Products (right)

N = 2 N = 2

O = 6 O = 6

H = 2 H = 2

Now the equation is balanced as we can see the number each type of atom is the same on the right and left side.

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↬ <img src="https://tex.z-dn.net/?f=what%20%5C%3Ais%5C%3A%20Pauli%20%5C%3A%20Exclusion%5C%3A%20Principle%20%5C%3A%3F" id="TexFor

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Explanation:

exclusion principle states that in a single atom no two electrons will have an identical set or the same quantum numbers (n, l, ml, and ms). To put it in simple terms, every electron should have or be in its own unique state (singlet state). There are two salient rules that the Pauli Exclusion Principle follows:

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2 years ago