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Minchanka [31]
2 years ago
11

↬

mula1" title="what \:is\: Pauli \: Exclusion\: Principle \:?" alt="what \:is\: Pauli \: Exclusion\: Principle \:?" align="absmiddle" class="latex-formula">​
Chemistry
1 answer:
Nikolay [14]2 years ago
8 0

Explanation:

exclusion principle states that in a single atom no two electrons will have an identical set or the same quantum numbers (n, l, ml, and ms). To put it in simple terms, every electron should have or be in its own unique state (singlet state). There are two salient rules that the Pauli Exclusion Principle follows:

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What led Marie Curie to draw the following conclusions? (b) A highly radioactive element, aside from uranium, occurs in pitchble
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Making repeated separations of the various substances in the pitchblende, Marie and Pierre used the Curie electrometer to identify the most radioactive fractions. They thus discovered that two fractions, one containing mostly bismuth and the other containing mostly barium, were strongly radioactive.

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Since it was no longer appropriate to call them “uranic rays,” Marie proposed a new name: “radioactivity.”

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6 0
2 years ago
can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g
V125BC [204]

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) <u>1278.50</u> = 6 sig figs

2) <u>12</u>0000 = 2 sig figs

3) <u>90027.00</u> = 7 sig figs

4) 0.00<u>53567</u> = 5 sig figs

5) <u>67</u>0 = 2 sig figs

6) 0.00<u>730</u> = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

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2 years ago
Direction: To compare and differentiate the animal and plant cell base on the presence and absence of certain organelles.Fill in
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Answer:

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Explanation:

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