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Orlov [11]
3 years ago
9

What is the ratio of the number of days in the week that do not begin with the letter "T" to the number of days in the week that

do begin with the letter "T"? (1 point)
Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

5:7

Step-by-step explanation:

The days in the week whose names don't begin with 'T' are Sunday, Monday, Wednesday, Friday, and Saturday. I counted them, and found that there are five (5) of them. Then I counted the number of days in a full week, no matter how they're spelled. I counted seven (7) that time. The ratio of 5 to 7 is. 5:7 or 5/7.

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Please help with this
pshichka [43]

Answer:

1800 ft^{3} (answer 1)

Step-by-step explanation:

the formula for volume is:

length x width x height

replace these with their corresponding numbers

10 x 10 x 18 = 1800 ft^{3}

Hope this was helpful :-)

5 0
3 years ago
The sum of two numbers is 34. The difference of the two numbers is 14. Find the two numbers.
harkovskaia [24]

Answer:24 and 10

Step-by-step explanation:24-10=34 24-10=14

6 0
4 years ago
Read 2 more answers
A man invested a certain amount of money in two separate projects in the ration 3:2. His profit was calculated on interest rates
Aneli [31]

Answer:

100,000

Step-by-step explanation:

Investment ratio = 3 : 2

Rate = 5% and 4% simple interest

Total interest after 2 years = 9200

Let total investment = t

(3/5t * 0.05 * 2) + (2/5t * 0.04 * 2) = 9200

3/5t * 0.1 + 2/5t * 0.08 = 9200

0.06t + 0.032t = 9200

0.092t = 9200

t = 9200 / 0.092

t = 100,000

3 0
3 years ago
HELP PLZ!!!
ss7ja [257]

Multiply 2x+3y=-1 by 5 and 3x-5y=10 by 3


3y*5=15y and -5y*3=-15y

Add -15y and 15y you have no y values left.


Your main focus is going to be on the y values. What can you multiply each y value by to get the same number so that when you add the positive and negative you get 0.




5 0
3 years ago
Read 2 more answers
Pls answer! I don’t know math @ all
Lana71 [14]

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

                                              (4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

$P(A)=\frac{N(A)}{N(S)}

$P(A)=\frac{6}{36}=\frac{1}{6}

$P(B)=\frac{N(B)}{N(S)}

$P(B)=\frac{9}{36}=\frac{1}{4}

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

P(A \cup B)=P(A)+P(B)

$P(A \cup B)=\frac{1}{6} +\frac{1}{4}

               $=\frac{2+3}{12} (Make the denominator same)

               $=\frac{5}{12}

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

8 0
3 years ago
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