Answer:D
Explanation:
Given
mass of A is twice the mass of B half the velocity of B
Suppose 
and 
be the average force exerted on A and B respectively
and According to Newton third law of motion Force on the body A is equal to Force on body B but opposite in direction as they are action and reaction force.
Thus 
and option d is correct
Hi there!
We can use the equation for the charge of a charging capacitor:
Using Capacitor equations:
Therefore, Cε equals the steady-state charge of the capacitor (the function approaches this value as t ⇒ ∞.
We can plug in the givens and solve.
Answer:
Incomplete question
Complete question:
a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?
Answer: 8m/s²
Explanation:
From the statement we deduced that acceleration varies inversely with mass where force was kept constant.
Therefore,
F/m = a or F = ma
For the first statement, substituting the mass and acceleration gives:
F = 44 x 4 = 88N
Applying the force above to the second mass gives us:
a = 88/11 = 8m/s²
we know that momentum is given as
P = mv
where P = momentum , m = mass , v = velocity
taking derivative both side relative to "t"
dP/dt = v (dm/dt)
we know that : dP/dt = F = force
hence
F = v (dm/dt)
given that :
dm/dt = rate of mass expelled = 1500 kg/s
v = velocity = 4 x 10⁴ m/s
hence , inserting the values in the above formula
F = (4 x 10⁴) (1500)
F = 6 x 10⁷ N
Answer:
Magnitude of the resultant vector is R = 6.81 m
Explanation:
Given :
Vector A having magnitude of 2.5 m
Vector A having direction 37 degree south of east.
Vector B having magnitude of 3.5 m
Vector B having direction 20 degree north of east.
Therefore, the angle between the two vectors is, θ = 37+20 = 57 degree
So, the resultant of the two vectors are given by
R = 6.81 m
