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2 years ago

Light of frequency 2.5 x 1015 Hz illuminates a

Physics

1 answer:

Nikitich [7]2 years ago

3 0

Answer:

h f = W + KE

Input energy equals work function plus KE of emitted electron

W = 6.63E-34 * 2.5E15 - 6.3 * 1.6E-19

W = 6.63 * 2.5 * 10^-19 - 10.1 * E-19 ev (1ev = 1.6E-19 J)

W = (16.6 - 10.1)E-19 = 6.5E-19 J

h f = 6.5E-19 J for electrons to be emitted with zero KE

f = 6.5E-19 / 6.63E-34 = .98E-15 / sec = 9.8E-14 / sec (threshold)

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Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

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2 years ago

Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi

Orlov [11]

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Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

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$1 min = 60 s$

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The original unit that we have is

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