The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value
Given :
Initial velocity , u = 0 m/s² .
To Find :
The acceleration of the cart.
Solution :
Since, acceleration is constant.
Using equation of motion :
![x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}](https://tex.z-dn.net/?f=x%20%3D%20ut%20%2B%20%5Cdfrac%7Bat%5E2%7D%7B2%7D%5C%5C%5C%5Cx%20%3D%20%5Cdfrac%7Bat%5E2%7D%7B2%7D)
Putting, t = 1 s and x = 4 m in above equation, we get :
![4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2](https://tex.z-dn.net/?f=4%20%3D%20%5Cdfrac%7Ba%281%29%5E2%7D%7B2%7D%5C%5C%5C%5Ca%20%3D%208%20%5C%20%20m%2Fs%5E2)
Therefore, the acceleration of the cart is 8 m/s².
Answer:
Not possible
Explanation:
= longitudinal modulus of elasticity = 35 Gpa
= transverse modulus of elasticity = 5.17 Gpa
= Epoxy modulus of elasticity = 3.4 Gpa
= Volume fraction of fibre (longitudinal)
= Volume fraction of fibre (transvers)
= Modulus of elasticity of aramid fibers = 131 Gpa
Longitudinal modulus of elasticity is given by
![E_{cl}=E_m(1-V_{\rho l})+E_fV_{\rho l}\\\Rightarrow 35=3.4(1-V_{\rho l})+131V_{\rho l}\\\Rightarrow 35=3.4-3.4V_{\rho l}+131V_{\rho l}\\\Rightarrow V_{\rho l}=\frac{35-3.4}{131-3.4}\\\Rightarrow V_{\rho l}=0.24764](https://tex.z-dn.net/?f=E_%7Bcl%7D%3DE_m%281-V_%7B%5Crho%20l%7D%29%2BE_fV_%7B%5Crho%20l%7D%5C%5C%5CRightarrow%2035%3D3.4%281-V_%7B%5Crho%20l%7D%29%2B131V_%7B%5Crho%20l%7D%5C%5C%5CRightarrow%2035%3D3.4-3.4V_%7B%5Crho%20l%7D%2B131V_%7B%5Crho%20l%7D%5C%5C%5CRightarrow%20V_%7B%5Crho%20l%7D%3D%5Cfrac%7B35-3.4%7D%7B131-3.4%7D%5C%5C%5CRightarrow%20V_%7B%5Crho%20l%7D%3D0.24764)
Transverse modulus of elasticity is given by
![E_{ct}=\frac{E_mE_f}{(1-V_{\rho t})E_f+V_{\rho t}E_m}\\\Rightarrow 5.17=\frac{3.4\times 131}{(1-V_{\rho t})131+V_{\rho t}3.4}\\\Rightarrow \frac{3.4\times 131}{5.17}-131=-127.6V_{\rho t}\\\Rightarrow V_{\rho t}=\frac{\frac{3.4\times 131}{5.17}-131}{-127.6}\\\Rightarrow V_{\rho t}=0.35148](https://tex.z-dn.net/?f=E_%7Bct%7D%3D%5Cfrac%7BE_mE_f%7D%7B%281-V_%7B%5Crho%20t%7D%29E_f%2BV_%7B%5Crho%20t%7DE_m%7D%5C%5C%5CRightarrow%205.17%3D%5Cfrac%7B3.4%5Ctimes%20131%7D%7B%281-V_%7B%5Crho%20t%7D%29131%2BV_%7B%5Crho%20t%7D3.4%7D%5C%5C%5CRightarrow%20%5Cfrac%7B3.4%5Ctimes%20131%7D%7B5.17%7D-131%3D-127.6V_%7B%5Crho%20t%7D%5C%5C%5CRightarrow%20V_%7B%5Crho%20t%7D%3D%5Cfrac%7B%5Cfrac%7B3.4%5Ctimes%20131%7D%7B5.17%7D-131%7D%7B-127.6%7D%5C%5C%5CRightarrow%20V_%7B%5Crho%20t%7D%3D0.35148)
![V_{\rho l}\neq V_{\rho t}](https://tex.z-dn.net/?f=V_%7B%5Crho%20l%7D%5Cneq%20V_%7B%5Crho%20t%7D)
Hence, it is not possible to produce a continuous and oriented aramid fiber.
Answer:
inertia of motion
Explanation:
it's because when a passenger is jumping from a bus his/her body is in motion after falling in a road he/she remains or tends to remain in the state of motion that is the reason
Flow of electrons through a copper wire