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3 years ago

A railroad car containing an angry bull is standing onthe

Physics

1 answer:

nata0808 [166]3 years ago

7 0

Answer:

$v_{f}$ = - M / m v

Explanation:

We must define a system formed by the wagon and the torro, in this case the forces of the movement are internal, so the moment is preserved, write the moment in two moments

Initial. Before the bull's movement, in this case the two are still

p₀ = 0

Final. The bull is moving

$p_{f}$ = M v + m $v_{f}$

p₀ = $p_{f}$

0 = M v + m $v_{f}$

We cleared the train speed

$v_{f}$ = - M / m v

The negative sign indicates that the train moves in the opposite direction of the bull

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If a magnetic field is to exert a force on a current-carrying wire, the field must have some vector component:

mash [69]

Answer:

D.) perpendicular to the current

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4 years ago

How does wavelength change depending on whether the pipe is open or closed?

il63 [147K]

Answer:

* in a tube with both ends open

λ = 2L / n n = 1, 2, 3,…

* tube with one end open and the other closed.

λ = 4L / n n = (2n ’+ 1 )

Explanation:

When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.

* in a tube with both ends open

in this case there are maximums at each end, so if the length of the had is L

λ = 2L 1st harmonic

λ = 2 L / 2 2nd harmonic

λ = 2L / 3

λ = 2L / n n = 1, 2, 3,…

* In the case of a tube with one end open and the other closed.

At the open end there is a belly and at the closed end a node

λ = 4L 1st harmonic

λ = 4L / 3 3rd harmonic

λ = 4L / 5

λ = 4L / n n = 1, 3, 5,… odd

n = (2n ’+ 1 ) where n’ are all integers

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3 years ago

What is the velocity of a motercycle traveling 13 km west in 3 hours

Soloha48 [4]

4.333333 kilometers an hour

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3 years ago

9. Captain America is chasing Red Skull. He plans to throw his shield to knock down Red Skull but needs to know how fast Red Sku

Sedaia [141]

Red Skull's relative velocity to Captain America, towards the left front of the

truck is approximately 33.23 m/s in a direction from the North of

approximately 9.18°.

Reasons:

Assumptions;

Taking the north direction as positive.

The activity takes place on the trucks.

The trucks are moving towards each other.

Solution:

Vector form of net speed of Red Skull, is given as follows;

v₁ = -( $\frac{\sqrt{2} }{2}$ × 3.5)·i + ( $\frac{\sqrt{2} }{2}$ × 3.5 + 12.5)·j

Vector form of the net speed of Captain America is given as follows;

v₂ = ( $\frac{\sqrt{2} }{2}$ × 4.0)·i - ( $\frac{\sqrt{2} }{2}$ × 4.0 + 15)·j

Relative velocity, v₁₂ = v₁ - v₂

∴ v₁₂ = (-( $\frac{\sqrt{2} }{2}$ × 3.5) - ( $\frac{\sqrt{2} }{2}$ × 4.0))·i + (( $\frac{\sqrt{2} }{2}$ × 3.5 + 12.5) + ( $\frac{\sqrt{2} }{2}$ × 4.0 + 15))·j

v₁₂ = $-\frac{ 15 \cdot \sqrt{2} }{4}$ ·i + $\frac{ 110 + 15 \cdot \sqrt{2} }{4}$ ·j

Red Skull's velocity relative to Captain America, v₁₂ = $-\frac{ 15 \cdot \sqrt{2} }{4}$ ·i + $\frac{ 110 + 15 \cdot \sqrt{2} }{4}$ ·j

v₁₂ ≈ -5.3·i + 32.8·j

Therefore;

Red Skull appears to be moving West at 5.3 m/s and North at 32.8 m/s

The direction is $arctan \left(\frac{32.8}{-5.3} \right) \approx -80.2^{\circ}$

Therefore;

Red Skull appear to be moving at 90° - 80.2° ≈ 9.18° towards the left front end of the truck moving North

The magnitude of the velocity, |v₁₂|, is given as follows;

$|v_{12}| = \sqrt{\left(-\frac{ 15 \cdot \sqrt{2} }{4}\right)^2 + \left(\frac{ 110 + 15 \cdot \sqrt{2} }{4}\right)^2} = \dfrac{ 5 \cdot \sqrt{130+33 \cdot\sqrt{2} } }{2} \approx 33.23$ ·

The magnitude of Red Skull's velocity relative to Captain America is,

therefore;

|v₁₂| ≈ 33.23 m/s

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3 years ago

A rope attached to a load of 175 kg bricks Ilifts the bricks with a steady acceleration of 0.12.m/s^2 straight up. What is the t

andrew-mc [135]

Answer:

Tension, T = 1736 N

Explanation:

It is given that,

Mass of bricks, m = 175 kg

A rope is attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12 m/s² in vertically upwards direction. let T is the tension in the rope. Using second equation of motion as :

T - mg = ma

T = ma + mg

T = m(a + g)

T = 175 kg ( 0.12 m/s² + 9.8 m/s² )

T = 1736 N

Hence, the tension in the wire is 1736 N.

4 0

3 years ago

Read 2 more answers