A railroad car containing an angry bull is standing onthe
1 answer:
Answer:
= - M / m v
Explanation:
We must define a system formed by the wagon and the torro, in this case the forces of the movement are internal, so the moment is preserved, write the moment in two moments
Initial. Before the bull's movement, in this case the two are still
p₀ = 0
Final. The bull is moving
= M v + m
p₀ =
0 = M v + m
We cleared the train speed
= - M / m v
The negative sign indicates that the train moves in the opposite direction of the bull
You might be interested in
Answer:
The force on q₁ due to q₂ is (0.00973i + 0.02798j) N
Explanation:
F₂₁ =
Where;
F₂₁ is the vector force on q₁ due to q₂
K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²
r₂₁ is the unit vector
|r₂₁| is the magnitude of the unit vector
|q₁| is the absolute charge on point charge one
|q₂| is the absolute charge on point charge two
r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)
|r₂₁| =
(|r₂₁|)² = 148.25
= 0.050938(0.19107i + 0.54933j) N
= (0.00973i + 0.02798j) N
Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N