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tino4ka555 [31]
2 years ago
11

Each side of a square is 6 2/3 m long. Find its Area

Mathematics
1 answer:
svlad2 [7]2 years ago
8 0

Answer: 80/3

Step-by-step explanation:

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Please help me it's urgent!
Crank

Answer:

y = 2x-5

y=-x+4

Step-by-step explanation:

Just need to solve the:

x+y=4

y-2x=-5

And we have:

x=3

y=1

Then replace x and y into the answer to find the correct one

7 0
2 years ago
If I have this sequence 2, 4, 6, ... I can describe the rule as
Andrews [41]

Answer:

I believe your rule would be (The rule is add 3)

Step-by-step explanation:

If you have -9 and you get to -6 that means you added an interval of 3

-9,-6,-3,0,3 is how it would continue

(The rule is add 3)

3 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Determine the intercepts of the line. x-intercept:( , ) y-intercept: ( , )​
sasho [114]

Answer:

y intercept is -10

x intercept is 3

the number at which the line intersects with the line is what it will be. Remember that the x intercept is horizontal and the y intercept is vertical

7 0
2 years ago
Solve x + 3y = 9. 3x – 3y = –13
Sloan [31]
Question \ 1) \ x + 3y = 9 


x=9-3y
 
  |Subtract \ 3y \ from \ both \ sides| 

Question \ 2) \ 3x - 3y = -13 


3(x-y)=-13
 
   |Factor \ out \ the \ common \ term \ 3|

x-y= \dfrac{13}{3}   |Divide \ both \ sides \ by \ 3|

x=- \dfrac{13}{3}+y  |Add \ y \ to \ both \ sides|

x=y- \dfrac{13}{3}  |Regroup \ terms|

7 0
3 years ago
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