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tino4ka555 [31]
3 years ago
11

Each side of a square is 6 2/3 m long. Find its Area

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer: 80/3

Step-by-step explanation:

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Https://brainly.com/question/22218539
Liula [17]

X=32

ABC=264

Look at image for explanation

3 0
3 years ago
What graph represents the piecewise function?
adoni [48]

Answer: Lower left corner

A piecewise function is basically a combination of other functions to make one single function. We can break up the given piecewise function into two parts:

f(x) = x-4

OR

f(x) = -2x

The f(x) will change depending on what x happens to be. If x is 0 or smaller, then we go with f(x) = x-4. Otherwise, if x is larger than 0, then we opt for f(x) = -2x.

To graph this, we basically graph y = x-4 and y = -2x together on the same coordinate system. We only graph y = x-4 if x is 0 or smaller. Likewise, we graph y = -2x when x > 0. This results in the graph shown in the lower left corner of your four answer choices.

Note: the closed circle means "include this point as part of the graph". The open circle means "exclude this point as part of the graph". So this is why the upper right corner is very close but not quite the answer we want.


5 0
3 years ago
marta has 7 more than half as many books as lucy. if l is the number of the books lucky has which expression could be use to fin
artcher [175]

Answer:

M= 1/2(x)+7

Step-by-step explanation:

Let M = Martha.

Let X = Number of Lucy's blocks.

Martha has half the amount as Lucy  - 1/2(x)

Then 7 more than that - 1/2 (x) + 7

3 0
2 years ago
Read 2 more answers
How to find volume of 3d objects
GarryVolchara [31]

Answer:

length x width x height

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feetquadratic equation h = - 16t^2+
Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

So we have

\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}

Solving the quadratic equation, we have

\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

3 0
1 year ago
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