HELP HELP HELP

Delvig [45]

Both angles will equal 180, as there is a line bisecting line AB to create the two angles.

Set up the following equation to have both angles equal 180:

$(x + 35) + (x - 23) = 180$

$x + 35 + x - 23 = 180$

Combine like terms:

$x + x = 2x$
$35 - 23 = 12$

$2x + 12 = 180$

Subtract 12 from both sides:

$2x = 168$

Divide both sides by 2:

$x = 84$

We now know the value of x, so plug it into the equation we set up:

$(84 + 35) + (84 - 23) = 180$

$119 + 61 = 180$

An obtuse angle will have a measure above 90 degrees. The number on the left side that is above 90 degrees is 119. This would be the measure for the obtuse angle.

The obtuse angle is 119 degrees wide.

8 0

3 years ago

What are the roots of y=x^2-3x

Crank

Answer:

Step-by-step explanation:

I believe that there was a typo in this question

Unfortunately, there are no roots of this equation without one of two things:

1. Another equation, and you could solve for the roots in a system of equations

2. The value of y is actually supposed to be 0

In the second case, you would solve it like this:

$x^{2}$ -3x = 0

factor out x

x(x-3) = 0

x = 0, x = 3

6 0

3 years ago

A rectangular storage container with an open top is to have a volume of 10 m3. The length of this base is twice the width. Mater

noname [10]

Answer:

$ 327.08

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

⇒ Length of the container = 2w,

If h be the height of the container,

So, the volume of the container = length × width × height

= 2w × w × h

= 2w² h

According to the question,

$2w^2h=10$

$\implies h=\frac{10}{2w^2}=\frac{5}{w^2}$

Now, the area of the base = length × width

$=2w^2$

Area of sides = 2 × length × height + 2 × width × height

$=2\times 2w\times h+2\times w\times h$

$=4w\times \frac{5}{w^2}+2w\times \frac{5}{w^2}$

$=\frac{20}{w}+\frac{10}{w}$

$=\frac{30}{w}$

Since, material for the base costs $20 per square meter and material for the sides costs $12 per square meter,

Hence, total cost,

$C(w) = 2w^2\times 20 +\frac{30}{w}\times 12$

$C(w)=40w^2+\frac{360}{w}$

Differentiating with respect to w,

$C'(w) = 80w - \frac{360}{w^2}$

Again differentiating with respect to w,

$C''(w) = 80 +\frac{720}{w^3}$

For maxima or minima,

C'(w) = 0

$80w - \frac{360}{w^2}=0$

$80w^3-360=0$

$80w^3=360$

$\implies w=\sqrt[3]{\frac{360}{80}}=1.65096362445\approx 1.651$

For w = 1.651, C''(w) = positive,

Thus, cost is minimum for width 1.651 meters,

And, the minimum cost = C(1.651) = $40(1.651)^2+\frac{360}{1.651}=\$327.081706869\approx \$ 327.08$

3 0

4 years ago

Help me with please and thanks

Alex73 [517]

Answer: b

Step-by-step explanation:

The answer is b because both sides of the table start with zero and both sides of the table have a continues pattern the y side(right). They are increasing by a set # of points(3).

I AM NOT POSITVE ABOUT THE ANSWER, BUT IF I HAD TO GUESS- B WOULD BE THE ANSWER! sorry if its wrong!

7 0

3 years ago

Read 2 more answers

A study showed that there are 16 vehicles for every 10 households. How many vehicles are there for 107 million households?

Komok [63]

$16v........10h \\x......107.000.000h \\\\ x=\frac{16*107.000.000}{10} \\\\ x=16*10.700.000 \\\\ \boxed{x=171.200.000 \ vehicles}$

5 0

3 years ago

Read 2 more answers