A recipe calls for five minutes of cooking time for three pounds of

Mathematics

1 answer:

irinina [24]2 years ago

3 0

Answer:

62 minutes are required to cook 37 pounds of meat.

Step-by-step explanation:

Let cooking time = y

pounds of meat = x

So, The equation for this linear model will be:

y=(5/3)*x

Now, we need to find how long would be needed to cook 37 pounds of meat?

So x= 37

Putting it in linear model and finding value of x

y=(5/3)*37

y=62 minutes

So, 62 minutes are required to cook 37 pounds of meat.

You might be interested in

What are the coordinates of the image produced by applying the composition / to the point (–5, 4)?

Rainbow [258]

Its D(5,-4) XD ;p
because I did it and got it right but don't take my word for it just ask the other suggestions <span />

3 0

2 years ago

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to: