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GuDViN [60]
2 years ago
7

Which of the following expressions is equal to 3x2 + 27 ?

Mathematics
1 answer:
djverab [1.8K]2 years ago
6 0

Step-by-step explanation:

The answer is provided in the options. The answer should have been A, if the question was 3x²-27.

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What is the area of a rectangle that is 2/6 foot long and 9/4 feet wide? Wrote an equation to represent the solution.
bezimeni [28]
I don’t know sorry I think the answer is 6/4
3 0
3 years ago
Which set of numbers is NOT in the solution set of the inequality x < 12?
pogonyaev

Answer:

D) {1,9,10,15,17}

Step-by-step explanation:

1, 9, and 10 are smaller than 12, however, 15 and 17 are not, therefore this is NOT a solution set to the inequality.

8 0
2 years ago
Solve a/-16 + 8 = 12.
iren [92.7K]

Answer:

355

Step-by-step explanation:  me

7 0
2 years ago
Due soon!! <br>Find the measure of GE¯¯¯¯¯¯¯¯. A. 14 B. 20 C. 15 D. 16
Nataly_w [17]

Answer:

D. 16

Step-by-step explanation:

GH^2 = GF \times GE

12^2 = 9 \times (9+x - 2)

144= 9 \times (7+x)

\frac{144}{9}= (7+x)

16= 7+x

16-7=x

9=x

GE = 9 + x - 2 = 9 + 9 - 2 = 18 - 2

GE = 16

4 0
3 years ago
Read 2 more answers
A random sample of 8 recent college graduates found that starting salaries for architects in New York City had a mean of $42,653
ycow [4]

Answer:

C. (36337.32, 48968.68)

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{9114}{\sqrt{8}} = 6315.68

The lower end of the interval is the sample mean subtracted by M. So it is 42653 - 6315.68 = 36337.32.

The upper end of the interval is the sample mean added to M. So it is 42653 + 6315.68 = 48968.68.

So the correct answer is:

C. (36337.32, 48968.68)

3 0
3 years ago
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