Answer:
Spectrum 1- Biphenyl
Spectrum 2 - Benzil
Spectrum 3 - Bibenzyl
Explanation:
<u>For Benzil:
</u>
<u>
</u>The Spectrum - 2 shows this compound.The C=O and C-H bond stretching observed at following values.


<u> For Biphenyl:
</u>
<u>
</u>Spectrum - 1 shows this compound.
There are stretching vibrations from
due to C-H stretching and C-C stretching respectively of aromatic ring only.
<u>For Bibenzyl:
</u>
Spectrum - 3 shows this compound
There are stretching vibrations at
due to C-H stretching and C-C stretching of aromatic ring.
Along with this, stretching vibrations at
due to C-H of alkyl.
Answer:
-100 kJ
Explanation:
We can solve this problem by applying the first law of thermodynamics, which states that:

where:
is the change in internal energy of a system
Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)
W is the work done by the system (it is positive if done by the system, negative if done on the system)
For the system in this problem we have:
W = +147 kJ is the work done by the system
Q = +47 kJ is the heat absorbed by the system
So , its change in internal energy is:

Answer:
The equation for this reaction is:
2Al(OH)3 (aq) + 3H2SO4 (l) ---> Al2(SO4)3 (s) + 6H2O (l)
Explanation:
Answer:
80.8 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 74.5 mL
Initial pressure (P₁) = 98.0 kPa
Final pressure (P₂) = 90.4 kPa
Final volume (V₂) =?
The final volume of the gas can be by using the Boyle's laws equation as follow:
P₁V₁ = P₂V₂
98 × 74.5 = 90.4 × V₂
7301 = 90.4 × V₂
Divide both side by 90.4
V₂ = 7301 / 90.4
V₂ = 80.8 mL
Thus, the volume of the gas is 80.8 mL