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Nesterboy [21]
3 years ago
6

Mr. Holmes is busy making a paper mache volcano that he is sure is going to win the national science fair contest. He only has r

oom in the volcano’s vent to put 100g of baking soda and 100ml of vinegar.
Mr. Holmes has 4 different concentrations of vinegar in his lab. The active ingredient in vinegar is acetic acid C2H4O2. Which concentration would give the most intense eruption in the volcano?

Bottle 1 shows that it has 44g of acetic acid in the 1L bottle.


Bottle 2 shows the vinegar has a molarity of 2M acetic acid


Bottle 3 shows it is 4% acetic acid by mass.


Bottle 4 when measured shows a pH of 7.
Chemistry
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

Bottle 2 shows the vinegar has a molarity of 2M acetic acid

Explanation:

2M of acetic acid has higher concentration of acetic acid as compared to other vinegar. In 2M of acetic acid is equals to 120 gram of acetic acid in 500 ml of water which is quiet higher than other concentration of acetic acid in vinegar which is 4%. So Mr. Holmes has to use 2M of acetic acid which will produced high intense eruption in the volcano and win the national science fair contest.

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What is the molarity of a solution that contains 224 grams of KOH in 2<br> liters of solution?
adelina 88 [10]

Answer:

\boxed {\boxed {\sf 2 \ M \ KOH}}

Explanation:

Molarity is a measure of concentration in moles per liter.

<h3>1. Grams to Moles </h3>

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

  • Potassium (K): 39.098 g/mol
  • Oxygen (O): 15.999 g/mol
  • Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

  • KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Multiply by the value we are converting: 224 g KOH

224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Flip the ratio so the units of grams KOH cancel.

224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}

224 *\frac {1 \ mol \ KOH}{56.105}

\frac {224}{56.105} \ mol \ KOH

3.992514036 \ mol \ KOH

<h3>2. Calculate Molarity </h3>

Remember molarity is moles per liter.

molarity = \frac{moles}{liters}

We just calculated the moles and we know there are 2 liters of solution.

molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}

molarity= 1.996257018 \ mol \ KOH/ L

<h3>3. Round and Convert Units </h3>

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.

  • 1.<u>9</u>96257018

The 9 in the tenths place tells us to round to 1 up to a 2

2 \ mol \ KOH/ L

Next, convert units. 1 mole per liter is equal to 1 molar or M.

2 \ M \ KOH

The molarity of the solution is <u>2  M  KOH</u>

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