Answer:
Manganese (Mn)
Explanation:
We know it's manganese because we are told it is an electrically neutral atom. This means it has the same number of protons and electrons. If it has 25 electrons, it has 25 protons. Protons tell us the atomic number of the atom, which also tells us the name of the element. Manganese is element 25 on the periodic table.
Answer:
24 atm.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 240 L
Initial pressure (P₁) = 2 atm
Final volume (V₂) = 20 L
Temperature = constant
Final pressure (P₂) =?
The final pressure required, can be obtained by using the Boyle's law equation as shown below:
P₁V₁ = P₂V₂
2 × 240 = P₂ × 20
480 = P₂ × 20
Divide both side by 20
P₂ = 480 / 20
P₂ = 24 atm
Thus, the final pressure required is 24 atm.
Am - it has an atomic number of 95 which is greater than 92.
Transuranium elements are elements with atomic levels greater than 92
Answer:
no
Explanation:
"Alkali metals are among the most reactive of all metals, which makes them suitable for specific and limited uses.
Alkali metals include lithium, sodium, potassium, rubidium, cesium and francium. These metals have large atomic radii and generally lose electrons during reactions. "
- Reference
Explanation:
1 literThe total of water is equal to 1000.0 g of water
we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water
1. For that find the molar mass
Na: 2 x 22.99= 45.98
S: 32.07
O: 4 x 16= 64
The total molar mass is 142.05
We have to find the number of moles, y
To find the number of moles divide 10.0g by 142.05 g/mol.
So the number of moles is 0.0704 moles.
For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.
The molarity would end up being 0.0704 M
The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter
