Answer:
The reaction decomposes more as T increases, therefore it is ENDOTHERMIC, meaning it requires energy to form CO and O₂.
Kp for each specie...
Kp = CO^2 O2 / (CO2)^2
for
T = 1500
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-0.048/100)= 0.99952
P-CO formed = 1-0.99952 = 0.00048
P-O2 = (1-0.99952)/2 = 0.00024
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.00048^2)(0.00024) / (0.99952^2) = 5.53*10^-11
T = 2500
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-17.6/100)= 0.824
P-CO formed = 1-0.824= 0.176
P-O2 = (1-0.176)/2 = 0.088
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.176^2)(0.088) / (0.824^2) =0.0040
T = 3000
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-54.8/100)= 0.452
P-CO formed = 1-0.452= 0.548
P-O2 = (1-0.452)/2 = 0.274
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.548^2)(0.274) / (0.452^2) =0.4027
Explanation:
